ISRO CS 2009

Question 31

A processor that has carry, overflow and sign flag bits as part of its program status word (PSW) performs addition of the following two 2’s complement numbers 01001101 and 11101001. After the execution of this addition operation, the status of the carry, overflow and sign flags, respectively will be

• 1, 1, 0
• 1, 0, 0
• 0, 1, 0
• 1, 0, 1

Question 32

The two numbers given below are multiplied using the Booth\'s algorithm Multiplicand: 0101 1010 1110 1110 Multiplier: 0111 0111 1011 1101 How many additions/subtractions are required for the multiplication of the above two numbers?

• 6
• 8
• 10
• 12

Question 33

The addition of 4-bit, two\'s complement, binary numbers 1101 and 0100 results in

• 0001 and an overflow
• 1001 and no overflow
• 0001 and no overflow
• 1001 and an overflow

Question 34

Which of the following statements about relative addressing mode is FALSE?

• It enables reduced instruction size
• It allows indexing of array element with same instruction
• It enables easy relocation of data
• It enables faster address calculation than absolute addressing

Question 35

Substitution of values for names (whose values are constants) is done in

• Local optimization
• Loop optimization
• Constant folding
• Strength reduction

Question 36

A root of equation f(x) = 0 can be computed to any degree of accuracy if a \'good\' initial approximation x₀ is chosen for which

• f (x₀) > 0
• f (x₀) f (x₀)" > 0
• f (x₀) f (x₀)" < 0
• f (x₀)" > 0

Question 37

Which of the following statement is correct

• △(U_kV_k) = U_k△V_k + V_k△U_k
• △(U_kV_k) = U_k+1△V_k + V_k+1△U_k
• △U_kV_k) = V_k+1△U_k + U_k△V_k
• △(U_kV_k) = U_k+1△V_k + V_k△U_k

Question 38

The cubic polynomial y(x) which takes the following values: y(0) = 1, y(1) = 0, y(2) = 1 y(3) = 10 is

• [Tex]\\x^3 - 2 x^2 + 1[/Tex]

• [Tex]\\x^3 + 3x^2 + 1[/Tex]

• [Tex]\\x^3 + 1[/Tex]

• [Tex]\\x^3 +2 x^2 + 1[/Tex]

Question 39

x = a cos(t), y = b sin(t) is the parametric form of

• Ellipse
• Hyperbola
• Circle
• Parabola

Question 40

The value of x at which y is minimum for y = x² − 3x + 1 is

• -3/2
• 3/2
• 0
• -5/4