A box contains 5 green, 4 yellow and 3 white balls. Three balls are drawn at random. What is the probability that they are not of the same color?
(A) 3/44
(B) 3/55
(C) 52/55
(D) 41/44
Answer: (D)
Explanation: Let S be the event of drawing 3 balls out of 12. Then,
n(S) = 12C3 = 220.
Let E be the event of drawing 3 balls of the same colour. Then,
n(E) = 5C3 + 4C3 + 3C3 = 10 + 4 + 1 = 15. And,
P(E) = n(E)/n(S) = 15/220 = 3/44.
Therefore, required probability = 1 – 3/44 = 41/44.
Quiz of this Question
Please comment below if you find anything wrong in the above post