Jack and Robert appeared in an examination. Robert scored 9 marks less than Jack. Jack’s score was 56% of the sum of their scores added together. Calculate their individual scores.
(A) 22 and 33
(B) 41 and 35
(C) 40 and 35
(D) 42 and 33
Answer: (D)
Explanation: Let Robert’s score be x. Then, Jack’s score = x+9.
Now, x+9 = 56% of [(x+9) + x]
⇒ x+9 = 14/25 × (2x + 9)
⇒ 25 × (x+9) = 14 × (2x+9)
⇒ 25x + 225 = 28x + 126
⇒ 3x = 99 ⇒ x = 33.
Therefore, Robert scored 33 marks and Jack scored 42 marks.
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QA – Placement Quizzes | Percentages | Question 8
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