What is the least number which when divided by 4, 5, 6 and 7 leaves a remainder 3, but when divided by 9 leaves no remainder?
(A)
1683
(B)
1263
(C)
843
(D)
423
Answer: (D)
Explanation:
LCM of 4,5,6,7 is 420
=>(420k+3) should be divisible by 9
if k =1, 423/9, remainder=0
When 423 is divided by 4, 5, 6, 7, it gives remainder 3 and when divided by 9 leaves a remainder 0.
So, the least number which when divided by 4, 5, 6 and 7 leaves a remainder 3, but when divided by 9 leaves no remainder is 423
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