Write a function rotate(ar[], d, n) that rotates arr[] of size n by d elements.
Rotation of the above array by 2 will make array
Algorithm :
Initialize A = arr[0..d-1] and B = arr[d..n-1] 1) Do following until size of A is equal to size of B a) If A is shorter, divide B into Bl and Br such that Br is of same length as A. Swap A and Br to change ABlBr into BrBlA. Now A is at its final place, so recur on pieces of B. b) If A is longer, divide A into Al and Ar such that Al is of same length as B Swap Al and B to change AlArB into BArAl. Now B is at its final place, so recur on pieces of A. 2) Finally when A and B are of equal size, block swap them.
Recursive Implementation:
# Wrapper over the recursive function leftRotateRec() # It left rotates arr by d. def leftRotate(arr, d, n):
leftRotateRec(arr, 0 , d, n);
def leftRotateRec(arr, i, d, n):
'''
* Return If number of elements to be
rotated is zero or equal to array size
'''
if (d = = 0 or d = = n):
return ;
'''
* If number of elements to be rotated
is exactly half of array size
'''
if (n - d = = d):
swap(arr, i, n - d + i, d);
return ;
''' If A is shorter '''
if (d < n - d):
swap(arr, i, n - d + i, d);
leftRotateRec(arr, i, d, n - d);
''' If B is shorter '''
else :
swap(arr, i, d, n - d);
''' This is tricky '''
leftRotateRec(arr, n - d + i, 2 * d - n, d);
''' UTILITY FUNCTIONS ''' ''' function to print an array ''' def printArray(arr, size):
for i in range (size):
print (arr[i], end = " " );
print ();
''' * This function swaps d elements starting at
* index fi with d elements starting at index si
'''
def swap(arr, fi, si, d):
for i in range (d):
temp = arr[fi + i];
arr[fi + i] = arr[si + i];
arr[si + i] = temp;
# Driver Code if __name__ = = '__main__' :
arr = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 ];
leftRotate(arr, 2 , 7 );
printArray(arr, 7 );
# This code is contributed by Rohit_ranjan |
Output:
3 5 4 6 7 1 2
Time Complexity: O(N), where N represents the size of the given array.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Iterative Implementation:
Here is iterative implementation of the same algorithm. Same utility function swap() is used here.
Time Complexity: O(n)
Please see following posts for other methods of array rotation:
https://www.geeksforgeeks.org/array-rotation/amp/
https://www.geeksforgeeks.org/program-for-array-rotation-continued-reversal-algorithm/amp/
Please write comments if you find any bug in the above programs/algorithms or want to share any additional information about the block swap algorithm.
Please refer complete article on Block swap algorithm for array rotation for more details!