Python – Remove Units from Value List

Sometimes, while working with Python value lists, we can have a problem in which we need to perform removal of units that come along with values. This problem can have direct application in day-day programming and data preprocessing. Let’s discuss certain ways in which this task can be performed.

Input : test_list = [“54 cm”, “23 cm”, “12cm”, “19 cm”], unit = “cm”
Output : [’54’, ’23’, ’12’, ’19’] 

Input : test_list = [“54 cm”], unit = “cm” 
Output : [’54’]

Method #1: Using regex() + list comprehension The combination of these functions can be used to solve this problem. In this, we approach by extracting just the numbers using regex, and remove rest of string units. 

Python3

# Python3 code to demonstrate working of
# Remove Units from Value List
# Using list comprehension + regex()
import re

# initializing list
test_list = ["54 kg", "23 kg", "12kg", "19  kg"]

# printing original list
print("The original list is : " + str(test_list))

# initializing unit
unit = "kg"

# Remove Units from Value List
# Using list comprehension + regex()
res = re.findall('\d+', ' '.join(test_list))

# printing result
print("List after unit removal : " + str(res))

Output : 

The original list is : ['54 kg', '23 kg', '12kg', '19  kg']
List after unit removal : ['54', '23', '12', '19']

Time complexity: O(n), where n is the length of the combined string of the list, because it has to traverse the string once to find all the digits using a regular expression. 
Auxiliary space: O(m), where m is the number of digits in the combined string, because it needs to store all the digits in a separate list.

Method #2: Using replace() + strip() + list comprehension The combination of above functions can be used to solve this problem. In this, we perform the task of replacing unit with empty string to remove it using replace() and stray spaces are handled using strip(). 

Python3

# Python3 code to demonstrate working of
# Remove Units from Value List
# Using replace() + strip() + list comprehension
import re

# initializing list
test_list = ["54 kg", "23 kg", "12kg", "19  kg"]

# printing original list
print("The original list is : " + str(test_list))

# initializing unit
unit = "kg"

# Remove Units from Value List
# Using replace() + strip() + list comprehension
res = [sub.replace(unit, "").strip() for sub in test_list]

# printing result
print("List after unit removal : " + str(res))

Output : 

The original list is : ['54 kg', '23 kg', '12kg', '19  kg']
List after unit removal : ['54', '23', '12', '19']

Time complexity: O(n), where n is the number of elements in the input list.
Auxiliary space: O(n), where n is the number of elements in the input list. This is because the list comprehension creates a new list with n elements. The space complexity of the other operations in the program is constant with respect to the input size.

Method #3 : Using split() and strip() methods

Python3

# Python3 code to demonstrate working of
# Remove Units from Value List


# initializing list
test_list = ["54 kg", "23 kg", "12kg", "19 kg"]

# printing original list
print("The original list is : " + str(test_list))

# initializing unit
unit = "kg"

# Remove Units from Value List
res=[]
for i in test_list:
    x=i.split(unit)[0]
    x=x.strip()
    res.append(x)

# printing result
print("List after unit removal : " + str(res))

Output

The original list is : ['54 kg', '23 kg', '12kg', '19 kg']
List after unit removal : ['54 ', '23 ', '12', '19 ']

Time Complexity : O(N)
Auxiliary Space : O(N)

Method 4: Using a loop and string methods:

Python3

test_list = ["54 kg", "23 kg", "12kg", "19  kg"]
unit = "kg"

res = []
for sub in test_list:
    if sub.endswith(unit):
        res.append(sub[:-len(unit)].strip())
    else:
        res.append(sub)

print("The original list is : " + str(test_list))
print("List after unit removal : " + str(res))

Output

The original list is : ['54 kg', '23 kg', '12kg', '19  kg']
List after unit removal : ['54', '23', '12', '19']

Time complexity: O(n), where n is the length of the input list test_list. The for loop iterates through each element in the list once, and the time complexity of each operation within the loop (i.e., endswith, append, strip, and len) is constant time, or O(1), so the total time complexity of the program is O(n).
Auxiliary space: O(n), since the output list res has the same length as the input list test_list. 

Method #5: Using map() and lambda function

This method uses the map() function and a lambda function to apply the replace() and strip() methods to each element in the list test_list.

Python3

test_list = ["54 kg", "23 kg", "12kg", "19 kg"]
unit = "kg"
res = list(map(lambda x: x.replace(unit, "").strip(), test_list))
print("List after unit removal : " + str(res))

Output

List after unit removal : ['54', '23', '12', '19']

Time complexity: O(n), where n is the length of the input list.
Auxiliary Space: O(n), because a new list is created to store the result.

Method #6: Using regular expression sub() method
We can use the sub() method from the re module to substitute the matching pattern (unit) with an empty string.

Python3

import re

# initializing list
test_list = ["54 kg", "23 kg", "12kg", "19  kg"]

# initializing unit
unit = "kg"

# Remove Units from Value List
# Using sub() method
res = [re.sub(unit, "", sub).strip() for sub in test_list]

# printing result
print("List after unit removal : " + str(res))

Output

List after unit removal : ['54', '23', '12', '19']

Time complexity: O(n) where n is the length of the list test_list. This is because we iterate through the list only once.
Auxiliary Space: O(n) because we create a new list of the same length as the original test_list.

Method #7: Using string slicing and isdigit() method

Step-by-step approach:

• Initialize an empty list called res.
• Iterate through each item in test_list using a for loop.
• Initialize an empty string called temp_str.
• For each item, remove the last len(unit) characters if the last characters in the item match the unit. This can be done by string slicing.
• Iterate through each character in the resulting string using another for loop.
• If the character is a digit, add it to temp_str.
• If the character is not a digit, append temp_str to res and break out of the inner loop.
• If the end of the string is reached, append temp_str to res.
• Return res.

Python3

# Python3 code to demonstrate working of
# Remove Units from Value List
# Using string slicing and isdigit() method

# initializing list
test_list = ["54 kg", "23 kg", "12kg", "19  kg"]

# printing original list
print("The original list is : " + str(test_list))

# initializing unit
unit = "kg"

# Remove Units from Value List
# Using string slicing and isdigit() method
res = []
for item in test_list:
    temp_str = ""
    if item.endswith(unit):
        item = item[:-len(unit)]
    for char in item:
        if char.isdigit():
            temp_str += char
        else:
            res.append(temp_str)
            break
    else:
        res.append(temp_str)

# printing result
print("List after unit removal : " + str(res))

Output

The original list is : ['54 kg', '23 kg', '12kg', '19  kg']
List after unit removal : ['54', '23', '12', '19']

Time complexity: O(n*m), where n is the length of test_list and m is the average length of each item in test_list.
Auxiliary space: O(n), where n is the length of test_list.