Python program to display half diamond pattern of numbers with star border

Given a number n, the task is to write a Python program to print a half-diamond pattern of numbers with a star border.

Examples:

Input: n = 5
Output:

*
*1*
*121*
*12321*
*1234321*
*123454321*
*1234321*
*12321*
*121*
*1*
*


Input: n = 3
Output:

*
*1*
*121*
*12321*
*121*
*1*
*

Approach:

• Two for loops will be run in this program in order to print the numbers as well as stars.
• First print * and then run for loop from 1 to (n+1) to print up to the rows in ascending order.
• In this particular for loop * will be printed up to i and then one more for loop will run from 1 to i+1 in order to print the numbers in ascending order.
• Now one more loop will run from i-1 to 0 in order to print the number in the reverse order.
• Now one star will be printed and this for loop will end.
• Now second for loop will run from n-1 to 0 to print the pattern as in the middle in which the numbers are in a reverse manner.
• In this for loop also the same work will be done as in first for loop.
• The required pattern will be displayed.

Below is the implementation of the above pattern:

Python3

# function to display the pattern up to n
def display(n):

    print("*")

    for i in range(1, n+1):
        print("*", end="")

        # for loop to display number up to i
        for j in range(1, i+1):
            print(j, end="")

        # for loop to display number in reverse direction
        for j in range(i-1, 0, -1):
            print(j, end="")

        print("*", end="")
        print()

    # for loop to display i in reverse direction
    for i in range(n-1, 0, -1):
        print("*", end="")
        for j in range(1, i+1):
            print(j, end="")

        for j in range(i-1, 0, -1):
            print(j, end="")

        print("*", end="")
        print()

    print("*")


# driver code
n = 5
print('\nFor n =', n)
display(n)

n = 3
print('\nFor n =', n)
display(n)

Output

For n = 5
*
*1*
*121*
*12321*
*1234321*
*123454321*
*1234321*
*12321*
*121*
*1*
*

For n = 3
*
*1*
*121*
*12321*
*121*
*1*
*