Python | math.isqrt() method

Math module in Python contains a number of mathematical operations, which can be performed with ease using the module. 
math.isqrt() method in Python is used to get the integer square root of the given non-negative integer value n. This method returns the floor value of the exact square root of n or equivalently the greatest integer a such that a² <= n.

Note: This method is new in Python version 3.8. 

Syntax: math.isqrt(n) 

Parameter:
n: A non-negative integer 

Returns: an integer value which represents the floor of exact square root of the given non-negative integer n. 

Code #1: Use of math.isqrt() method

Python3

# Python Program to explain
# math.isqrt() method


import math

n = 10

# Get the floor value of
# exact square root of n
sqrt = math.isqrt(n)
print(sqrt)

n = 100

# Get the floor value of
# exact square root of n
sqrt = math.isqrt(n)
print(sqrt)

Output:

3
10

Code #2: Use of math.isqrt() method to check whether the given integer is a perfect square.

Python3

# Python Program to explain
# math.isqrt() method


import math


def isPerfect(n):

    # Get the floor value of
    # exact square root of n
    sqrt = math.isqrt(n)

    if sqrt * sqrt == n:
        print(f"{n} is perfect square")

    else :
        print(f"{n} is not a perfect square")



# Driver's code
isPerfect(100)
isPerfect(10)

Output:

100 is perfect square
10 is not a perfect square

Code #3: Use of math.isqrt() method to find the next perfect square of n.

Python3

# Python Program to explain
# math.isqrt() method


import math

n = 11


def Next(n):

    # Get the ceiling of
    # exact square root of n
    ceil = 1 + math.isqrt(n)

    # print the next perfect square of n
    print("Next perfect square of {} is {}".
          format(n, ceil*ceil))


# Driver's code
Next(11)
Next(37)

Output:

Next perfect square after 11 is 16
Next perfect square after 37 is 49