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Python | Lowercase first character of String

The problem of capitalizing a string is quite common and has been discussed many times. But sometimes, we might have a problem like this in which we need to convert the first character of the string to lowercase. Let us discuss certain ways in which this can be performed. 

Method #1: Using string slicing + lower() This task can easily be performed using the lower method which lowercase the characters provided to it and slicing can be used to add the remaining string after the lowercase first character. 






# Python3 code to demonstrate working of
# Lowercase first character of String
# Using lower() + string slicing
 
# initializing string
test_str = "GeeksforGeeks"
 
# printing original string
print("The original string is : " + str(test_str))
 
# Using lower() + string slicing
# Lowercase first character of String
res = test_str[0].lower() + test_str[1:]
 
# printing result
print("The string after lowercasing initial character : " + str(res))

Output : 
The original string is : GeeksforGeeks
The string after lowercasing initial character : geeksforGeeks

Time Complexity: O(n)
Auxiliary Space: O(n)



Method #2: Using lambda + string slicing + lower() The recipe of lambda function has to be added if we need to perform the task of handling None values or empty strings as well, and this becomes essential to handle edge cases. 




# Python3 code to demonstrate working of
# Lowercase first character of String
# Using lower() + string slicing + lambda
 
# initializing string
test_str = "GeeksforGeeks"
 
# printing original string
print("The original string is : " + str(test_str))
 
# Using lower() + string slicing + lambda
# Lowercase first character of String
 
 
def res(test_str): return test_str[:1].lower() +
 
 
test_str[1:] if test_str else ''
 
 
# printing result
print("The string after lowercasing initial character : " + str(res(test_str)))

Output : 
The original string is : GeeksforGeeks
The string after lowercasing initial character : geeksforGeeks

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #3 : Using replace() method without slicing




# Python3 code to demonstrate working of
# Lowercase first character of String
 
# initializing string
test_str = "GeeksforGeeks"
 
# printing original string
print("The original string is : " + str(test_str))
 
test_str=test_str.replace(test_str[0],test_str[0].lower(),1)
 
# printing result
print("The string after lowercasing initial character : " + str(test_str))

Output
The original string is : GeeksforGeeks
The string after lowercasing initial character : geeksforGeeks

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #4 : Using slicing and index() method




# Python3 code to demonstrate working of
# Lowercase first character of String
 
# initializing string
test_str = "GeeksforGeeks"
 
# printing original string
print("The original string is : " + str(test_str))
 
loweralphabets="abcdefghijklmnopqrstuvwxyz"
upperalphabets="ABCDEFGHIJKLMOPQRSTUVWXYZ"
res=loweralphabets[upperalphabets.index(test_str[0])]+test_str[1:]
# printing result
print("The string after lowercasing initial character : " + str(res))

Output
The original string is : GeeksforGeeks
The string after lowercasing initial character : geeksforGeeks

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #5 : Using ord(),chr() functions 




# Python3 code to demonstrate working of
# Lowercase first character of String
 
# initializing string
test_str = "GeeksforGeeks"
 
# printing original string
print("The original string is : " + str(test_str))
result = ""
if(ord(test_str[0]) <= ord('Z')):
    result = chr(ord(test_str[0])+32)
    result += test_str[1:]
else:
    result = test_str
 
# printing result
print("The string after lowercasing initial character : " + str(result))

Output
The original string is : GeeksforGeeks
The string after lowercasing initial character : geeksforGeeks

Method #7: Using Regular Expression and the re.sub() function

This method involves using the re.sub() function to replace the first character of the string with its lowercase form.

Step-by-step approach:

Below is the implementation of the above approach:




import re
 
# initializing string
test_str = "GeeksforGeeks"
 
# printing original string
print("The original string is : " + str(test_str))
 
# Using Regular Expression and the re.sub() function
# Lowercase first character of String
 
def repl_func(match):
    return match.group(1).lower()
 
result = re.sub(r'^(.)', repl_func, test_str)
 
# printing result
print("The string after lowercasing initial character : " + str(result))

Output
The original string is : GeeksforGeeks
The string after lowercasing initial character : geeksforGeeks

Time complexity: O(n) where n is the length of the string.
Auxiliary space: O(n) where n is the length of the string.


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