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Python | Locking without Deadlocks

This article focuses on dealing with how to get more than one lock at a time if a multithread program is given along with avoiding the deadlocks. 

Multithread programs – Due to the threads that keep on attempting to get multiple locks at once, these are very much prone to deadlocks. Understanding it with an example – a lock is already been acquired by a thread and then a second lock is attempted by the block then in that case, the program can freeze as the thread can potentially block the progress of other threads. 
 



Solution: 

Code #1: Implementing the solution using a context manager.
 






# importing libraries
import threading
from contextlib import contextmanager
 
# threading to stored information
_local = threading.local()
 
 
@contextmanager
def acquire(*lock_state_state):
 
    # Object identifier to sort the lock
    lock_state_state = sorted(lock_state_state, key=lambda a: id(a))
 
    # checking the validity of previous locks
    acquired = getattr(_local, 'acquired', [])
    if acquired and max(id(lock_state) for
                        lock_state in acquired) >= id(lock_state_state[0]):
        raise RuntimeError('lock_state Order Violation')
 
    # Collecting all the lock state.
    acquired.extend(lock_state_state)
    _local.acquired = acquired
 
    try:
    for lock_state in lock_state_state:
        lock.acquire()
    yield
    finally:
 
        # locks are released in reverse order.
        for lock_state in reversed(lock_state_state):
            lock_state.release()
        del acquired[-len(lock_state_state):]

Locks are acquired in the normal way using the context manager and for performing this task acquire() function is used as there was more than one lock as shown in the code below : 
 

Code #2 : 




# threads
import threading
 
# creating locks
lock_state_1 = threading.Lock()
lock_state_2 = threading.Lock()
 
# using acquire as there are more than one lock
 
 
def thread_1():
    while True:
        with acquire(lock_state_1, lock_state_2):
            print('Thread-1')
 
 
def thread_2():
    while True:
        with acquire(lock_state_2, lock_state_1):
            print('Thread-2')
 
 
t1 = threading.Thread(target=thread_1)
 
# daemon thread runs without blocking
# the main program from exiting
t1.daemon = True
t1.start()
 
t2 = threading.Thread(target=thread_2)
t2.daemon = True
t2.start()

Code #3 :  




# threads
import threading
 
# creating locks
lock_state_1 = threading.Lock()
lock_state_2 = threading.Lock()
 
 
def thread_1():
    while True:
        with acquire(lock_state_1):
            with acquire(lock_state_2):
                print('Thread-1')
 
 
def thread_2():
    while True:
        with acquire(lock_state_2):
            with acquire(lock_state_1):
                print('Thread-2')
 
 
t1 = threading.Thread(target=thread_1)
 
# daemon thread runs without blocking
# the main program from exiting
t1.daemon = True
t1.start()
 
t2 = threading.Thread(target=thread_2)
t2.daemon = True
t2.start()

On running this version of the program, one of the threads will crash with an exception such as : 
 

Exception in thread Thread-1:
Traceback (most recent call last):
    File "/usr/HP/lib/python3.3/threading.py", line 639, in _bootstrap_inner
        self.run()
    File "/usr/HP/lib/python3.3/threading.py", line 596, in run
        self._target(*self._args, **self._kwargs)
    File "deadlock.py", line 49, in thread_1
        with acquire(y_lock):
    File "/usr/HP/lib/python3.3/contextlib.py", line 48, in __enter__
        return next(self.gen)
    File "deadlock.py", line 17, in acquire
        raise RuntimeError("Lock Order Violation")
RuntimeError: Lock Order Violation

Each thread remembers the lock been already acquired that’s why it’s been showing this error. The ordering constraints that acquired the locks are also enforced and a list of previously acquired locks is checked by the acquire() method.
 


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