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Python – Incremental and Cyclic Repetition of List Elements

Sometimes, while working with Python lists, we can have a problem in which we need to repeat elements K times. But we can have variations in this and have to repeat elements in cyclic and incremental way. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop + enumerate() 
This is brute force way in which this task can be performed. In this, we iterate the elements and perform the required number of repetition using mod operator and multiplication logic.






# Python3 code to demonstrate
# Incremental and Cyclic Repetition of List Elements
# using loop + enumerate()
 
# Initializing list
test_list = ['g', 'f', 'g', 'C', 'S']
 
# printing original list
print("The original list is : " + str(test_list))
 
# Initializing range
i, j = 2, 4
 
# Incremental and Cyclic Repetition of List Elements
# using loop + enumerate()
res = []
temp = list(range(i, j + 1))
for idx, ele in enumerate(test_list):
    res.append(ele * temp[idx % len(temp)])
     
# printing result
print ("Repetition List is : " + str(res))

Output : 
The original list is : ['g', 'f', 'g', 'C', 'S']
Repetition List is : ['gg', 'fff', 'gggg', 'CC', 'SSS']

 

Time complexity: O(n), where n is the length of the input list.
Auxiliary space: O(n), as we are using a new list to store the repeated elements.



Method #2 : Using cycle() + loop + zip() 
The combination of these tasks can also be used to perform this task. In this, we iterate using loop and cycling and repetition is performed using cycle().
 




# Python3 code to demonstrate
# Incremental and Cyclic Repetition of List Elements
# using cycle() + loop + zip()
from itertools import cycle
 
# Initializing list
test_list = ['g', 'f', 'g', 'C', 'S']
 
# printing original list
print("The original list is : " + str(test_list))
 
# Initializing range
i, j = 2, 4
 
# Incremental and Cyclic Repetition of List Elements
# using cycle() + loop + zip()
res = []
for k, l in zip(cycle(range(i, j + 1)), test_list):
    res.append(k * l)
     
# printing result
print ("Repetition List is : " + str(res))

Output : 
The original list is : ['g', 'f', 'g', 'C', 'S']
Repetition List is : ['gg', 'fff', 'gggg', 'CC', 'SSS']

 

Time complexity: O(n), where n is the length of the input list test_list. 
Auxiliary space: O(n), where n is the length of the input list test_list.

Method 3: Use list comprehension

Step-by-step approach:

Below is the implementation of the above approach:




# Python3 code to demonstrate
# Incremental and Cyclic Repetition of List Elements
# using list comprehension
 
# Initializing list
test_list = ['g', 'f', 'g', 'C', 'S']
 
# printing original list
print("The original list is : " + str(test_list))
 
# Initializing range
i, j = 2, 4
 
# Incremental and Cyclic Repetition of List Elements
# using list comprehension
res = [((idx % (j - i + 1) + i) * val) for idx, val in enumerate(test_list)]
 
# printing result
print("Repetition List is : " + str(res))

Output
The original list is : ['g', 'f', 'g', 'C', 'S']
Repetition List is : ['gg', 'fff', 'gggg', 'CC', 'SSS']

Time complexity: O(n), where n is the length of the input list test_list.
Auxiliary space: O(n), where n is the length of the input list test_list. This is the space required to store the output list res.


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