The premise of the puzzle is as follows: You have two bottles that are packed with 10 liters of water each. Your goal is to take 2 liters of water in two empty bottles of 4 liters and 5 liters, respectively. However, there is a catch – you can only use four bottles that are packed with 10 liters of water, packed with 10 liters of water, an empty bottle of 5 liters, and an empty bottle of 4 liters to switch the water. Throwing or wasting water is not allowed.
Taking 2-2 Liters of Water
Solution:
This is a classic water-pouring puzzle that requires some creative thinking to solve. Here’s one way to do it:
- At the initial state, we have two bottles filled with 10 liters of water and one empty bottle of 4-liter, and one empty bottle of 5-liter.
- Now let us name the first 10-liter bottle as A, 2nd 10-liter bottle as B, the third 4-liter bottle as C, and the fourth 5-liter bottle as D.
- Transfer 5-liter water from Bottle B to Bottle D.
- Now, transfer water from Bottle D to Bottle C.
- Now, empty water from Bottle C to Bottle B which makes it 9 liters in it.
- Transfer leftover water from Bottle D to C.
- Transfer water from Bottle A to D, which makes 5 liters in both bottles.
- Now transfer the water from bottle D to Bottle C and make it full that is Bottle C = 4 liters filled.
- Now Bottle D is left with 2 liters of water and therefore we achieve one bottle filled with only 2 liters of water.
- Now transfer complete water from Bottle C to Bottle B and make it completely full.
- This way we are left with only 2 liters in Bottle C, 10 liters in Bottle B, and 6 liters in bottle A.
- Therefore, we have achieved 2nd bottle with 2 liters of water only.
Below are the steps to solve the above problem:
Taking 2-2 Liters of Water
By following these steps, you will be able to achieve your goal of having 2 liters of water in the empty bottle of 5 liters and 2 liters of water in the empty bottle of 4 liters. You have not wasted any water and have followed the rules of the puzzle.