Given the total number of Rupees in a bag and the ratio of coins. The bag contains only 1 Rs, 50 paise, 25 paise coins in X, Y, Z, ratio. The task is to determine the number of 1 Rs coins, 50 Paise coins, and 25 paise coins So that after summation of all these we again get the total rupees given.
Examples:
Input: totalRupees = 1800, X = 1, Y = 2, Z = 4 Output: 1 rupees coins = 600 50 paisa coins = 1200 25 paisa coins = 2400 Input: totalRupees = 2500, X = 2, Y = 4, Z = 2 Output: 1 rupees coins = 555 50 paisa coins = 1110 25 paisa coins = 2220
Approach:
Let the ratio in which 1 Rs, 50 paise and 25 paise coin is divided is 1:2:4
Now,
1 Rs coins in a bag is 1x.
50 paise coins in a bag is 2x.
25 paise coins in a bag is 4x.
Now convert these paise into Rupees.
So,
x coins of 1 Rs each, the total value is x rupees.
2x coins of 50 paise i.e (1 / 2) rupees each, the total value is x rupees.
4x coins of 25 paise i.e (1 / 4) rupees each, the total is x rupees.
Therefore,
3x = 1800
x = 600
1 rupee coins = 600 * 1 = 600
50 paisa coins = 600 * 2 = 1200
25 paisa coins = 600 * 4 = 2400
Below is the implementation of the above approach:
// C++ implementation of above approach #include <bits/stdc++.h> using namespace std;
// function to calculate coin. int coin( int totalRupees, int X, int Y, int Z)
{ float one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2.0);
twentyfive = ((Z * 1) / 4.0);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return result;
} // Driver code int main()
{ int totalRupees = 1800;
int X = 1, Y = 2, Z = 4;
int Rupees = coin(totalRupees, X, Y, Z);
cout << "1 rupee coins = " << Rupees * 1 << endl;
cout << "50 paisa coins = " << Rupees * 2 << endl;
cout << "25 paisa coins = " << Rupees * 4 << endl;
return 0;
} |
// Java implementation of above approach import java.io.*;
class GFG {
// function to calculate coin. static int coin( int totalRupees, int X, int Y, int Z)
{ float one = 0 , fifty = 0 , twentyfive = 0 ,
result = 0 , total = 0 ;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1 ;
fifty = ((Y * 1 ) / 2 );
twentyfive = ((Z * 1 ) / 4 );
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return ( int )result;
} // Driver code public static void main (String[] args) {
int totalRupees = 1800 ;
int X = 1 , Y = 2 , Z = 4 ;
int Rupees = coin(totalRupees, X, Y, Z);
System.out.println( "1 rupee coins = " + Rupees * 1 );
System.out.println( "50 paisa coins = " + Rupees * 2 );
System.out.println( "25 paisa coins = " + Rupees * 4 );
}
} //This code is contributed by inder_verma. |
# Python3 implementation of above approach # function to calculate coin. def coin(totalRupees, X, Y, Z):
# Converting each of them in rupees.
# As we are given totalRupees = 1800
one = X * 1
fifty = ((Y * 1 ) / 2.0 )
twentyfive = ((Z * 1 ) / 4.0 )
total = one + fifty + twentyfive
result = ((totalRupees) / total)
return int (result)
# Driver code if __name__ = = '__main__' :
totalRupees = 1800
X, Y, Z = 1 , 2 , 4
Rupees = coin(totalRupees, X, Y, Z)
print ( "1 rupee coins = " , Rupees * 1 )
print ( "50 paisa coins = " , Rupees * 2 )
print ( "25 paisa coins = " , Rupees * 4 )
# This code is contributed by # Sanjit_Prasad |
// C# implementation of above approach using System;
class GFG
{ // function to calculate coin. static int coin( int totalRupees, int X,
int Y, int Z)
{ float one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2);
twentyfive = ((Z * 1) / 4);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return ( int )result;
} // Driver code public static void Main ()
{ int totalRupees = 1800;
int X = 1, Y = 2, Z = 4;
int Rupees = coin(totalRupees, X, Y, Z);
Console.WriteLine( "1 rupee coins = " + Rupees * 1);
Console.WriteLine( "50 paisa coins = " + Rupees * 2);
Console.WriteLine( "25 paisa coins = " + Rupees * 4);
} } // This code is contributed by inder_verma |
<?php // PHP implementation of above approach //function to calculate coin function coin( $totalRupees , $X , $Y , $Z )
{ $one = 0;
$fifty = 0;
$twentyfive = 0;
$result = 0;
$total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
$one = $X * 1;
$fifty = (( $Y * 1) / 2.0);
$twentyfive = (( $Z * 1) / 4.0);
$total = $one + $fifty + $twentyfive ;
$result = (( $totalRupees ) / $total );
return $result ;
} // Driver Code $totalRupees = 1800;
$X = 1;
$Y = 2;
$Z = 4;
$Rupees = coin( $totalRupees , $X , $Y , $Z );
echo "1 rupee coins = " , $Rupees * 1, "\n" ;
echo "50 paisa coins = " , $Rupees * 2, "\n" ;
echo "25 paisa coins = " , $Rupees * 4, "\n" ;
// This code is contributed // by Shashank_Sharma. ?> |
<script> // Javascript implementation of above approach // function to calculate coin. function coin(totalRupees, X, Y, Z)
{ var one = 0, fifty = 0, twentyfive = 0,
result = 0, total = 0;
// Converting each of them in rupees.
// As we are given totalRupees = 1800
one = X * 1;
fifty = ((Y * 1) / 2.0);
twentyfive = ((Z * 1) / 4.0);
total = one + fifty + twentyfive;
result = ((totalRupees) / total);
return result;
} // Driver code var totalRupees = 1800;
var X = 1, Y = 2, Z = 4;
var Rupees = coin(totalRupees, X, Y, Z);
document.write( "1 rupee coins = " + Rupees * 1 + "<br>" );
document.write( "50 paisa coins = " + Rupees * 2 + "<br>" );
document.write( "25 paisa coins = " + Rupees * 4 + "<br>" );
</script> |
1 rupee coins = 600 50 paisa coins = 1200 25 paisa coins = 2400
Time Complexity: O(1)
Auxiliary Space: O(1)