Given a number N. The task is to write a program to find the Nth term of the below series:
1, 6, 17, 34, 56, 86, 121, 162, …..(N Terms)
Examples:
Input: N = 4 Output: 34 For N = 4 4th Term = ( 3 * 4 * 4 - 4 * 4 + 2) = 34 Input: N = 10 Output: 261
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// C++ program to find the N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... #include <iostream> #include <math.h> using namespace std;
// calculate Nth term of series int nthTerm( int n)
{ return 3 * pow (n, 2) - 4 * n + 2;
} // Driver code int main()
{ int N = 4;
cout << nthTerm(N) << endl;
return 0;
} |
Java
// Java program to find the N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... public class GFG {
// calculate Nth term of series
static int nthTerm( int n)
{
return 3 * ( int ) Math.pow(n, 2 ) - 4 * n + 2 ;
}
// Driver code
public static void main(String args[])
{
int N = 4 ;
System.out.println(nthTerm(N));
}
// This Code is contributed by ANKITRAI1
} |
Python3
# Python program to find the # N-th term of the series: # 1, 6, 17, 34, 56, 86, 121, 162, ..... # calculate Nth term of series def nthTerm(n):
return 3 * pow (n, 2 ) - 4 * n + 2
# Driver code N = 4
print (nthTerm(N))
# This code is contributed by # Sanjit_Prasad |
C#
// C# program to find the // N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... using System;
class GFG
{ // calculate Nth term of series static int nthTerm( int n)
{ return 3 * ( int ) Math.Pow(n, 2) -
4 * n + 2;
} // Driver code public static void Main()
{ int N = 4;
Console.Write(nthTerm(N));
} } // This code is contributed // by ChitraNayal |
PHP
<?php // PHP program to find the // N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... // calculate Nth term of series function nthTerm( $n )
{ return 3 * pow( $n , 2) -
4 * $n + 2;
} // Driver code $N = 4;
echo nthTerm( $N ). "\n" ;
// This code is contributed // by ChitraNayal ?> |
Javascript
<script> // JavaScript program to find the N-th term of the series: // 1, 6, 17, 34, 56, 86, 121, 162, ..... // calculate Nth term of series function nthTerm(n)
{ return 3 * Math.pow(n, 2) - 4 * n + 2;
} // Driver code let N = 4; document.write( nthTerm(N) );
// This code contributed by gauravrajput1 </script> |
Output:
34
Time Complexity: O(1), since there is no loop or recursion.
Space Complexity: O(1) since using constant variables