Percentage increase in volume of the sphere if radius is increased by a given percentage

Given here is a sphere, whose radius is increased by a given percentage. The task is to find the percentage increase in the volume of the sphere.
Examples:

Input: x = 10
Output: 33.1%

Input: x = 50
Output: 237.5%

Approach: 

• Let, the radius of the sphere = a
• given percentage increase = x%
• volume before increase = 4/3*πa^3
• new radius after increase = a + ax/100
• so, new volume = 4/3*π(a^3 + (ax/100)^3 + 3a^3x/100 + 3a^3x^2/10000)
• change in volume = 4/3*π((ax/100)^3 + 3a^3x/100 + 3a^3x^2/10000)
• percentage increase in volume = (4/3*π*((ax/100)^3 + 3a^3x/100 + 3a^3x^2/10000)/4/3*π*a^3) * 100 = x^3/10000 + 3x + 3x^2/100

C++

// C++ program to find percentage increase
// in the volume of the sphere
// if radius is increased by a given percentage

#include <bits/stdc++.h>
using namespace std;

void newvol(double x)
{
    cout << "percentage increase in the"
         << " volume of the sphere is "
         << pow(x, 3) / 10000 + 3 * x
                + (3 * pow(x, 2)) / 100
         << "%" << endl;
}

// Driver code
int main()
{
    double x = 10;
    newvol(x);
    return 0;
}

Java

// Java program to find percentage increase
// in the volume of the sphere
// if radius is increased by a given percentage
import java.io.*;

class GFG
{

static void newvol(double x)
{
    System.out.print( "percentage increase in the"
        + " volume of the sphere is "
        +( Math.pow(x, 3) / 10000 + 3 * x
                + (3 * Math.pow(x, 2)) / 100)
        + "%");
}

// Driver code
public static void main (String[] args)
{
        double x = 10;
    newvol(x);
}
}

// This code is contributed by anuj_67..

Python3

# Python3 program to find percentage increase
# in the volume of the sphere
# if radius is increased by a given percentage

def newvol(x):

    print("percentage increase in the"
        " volume of the sphere is "
        ,pow(x, 3) / 10000 + 3 * x
                + (3 * pow(x, 2)) / 100
            ,"%")

# Driver code
x = 10.0
newvol(x)

# This code is contributed mohit kumar 29

C#

// C# program to find percentage increase
// in the volume of the sphere
// if radius is increased by a given percentage
using System;

class GFG
{

static void newvol(double x)
{
    Console.WriteLine( "percentage increase in the"
        + " volume of the sphere is "
        +( Math.Pow(x, 3) / 10000 + 3 * x
                + (3 * Math.Pow(x, 2)) / 100)
        + "%");
}

// Driver code
public static void Main ()
{
    double x = 10;
    newvol(x);
}
}

// This code is contributed by anuj_67..

Javascript

<script>
// javascript program to find percentage increase
// in the volume of the sphere
// if radius is increased by a given percentage
function newvol(x)
{
    document.write( "percentage increase in the"
        + " volume of the sphere is "
        +( Math.pow(x, 3) / 10000 + 3 * x
                + (3 * Math.pow(x, 2)) / 100)
        + "%");
}

// Driver code
var x = 10;
newvol(x);

// This code is contributed by 29AjayKumar
</script>

Output:

percentage increase in the volume of the sphere is 33.1%

Time Complexity: O(1)

Auxiliary Space: O(1) since using constant variables