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numpy.ma.ediff1d() function in Python

numpy.ma.ediff1d() function return the differences between consecutive elements of an array.

Syntax : numpy.ma.ediff1d(arr, to_end = None, to_begin = None) 



Parameters : 
arr : [array_like] Input array. 
to_end : [array_like, optional] Number to append at the end of the returned differences. 
to_begin : [array_like, optional] Number to prepend at the beginning of the returned differences. 

Return : Return the differences between consecutive elements of an array. 



Code #1:




# Python program explaining
# numpy.ma.ediff1d() function
  
# importing numpy as geek
import numpy as geek
  
arr = geek.array([3, 5, 8, 4, 12])
  
gfg = geek.ma.ediff1d(arr)
  
print(gfg)

Output:

[ 2  3 -4  8]

Code #2:




# Python program explaining
# numpy.ma.ediff1d() function
  
# importing numpy as geek
import numpy as geek
  
arr = geek.array([3, 5, 8, 4, 12])
  
gfg = geek.ma.ediff1d(arr, to_begin=geek.array([-23, 0]), to_end=25)
  
print(gfg)

Output:

[-23 0 2 3 -4 8 25]
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