# Nth term where K+1th term is product of Kth term with difference of max and min digit of Kth term

Given two integers N and D, the task is to find the value of F(N) where the value of F(1) is D, where F(K) is given as:

Examples:

Input: N = 3, D = 487
Output: 15584
Explanation:
As F(1) = 487,
F(2) = 487 * (maxDigit(487) – minDigit(487)) = 487 * 4 = 1948
F(3) = 1948 * (maxDigit(1948) – minDigit(1948)) = 1948 * 8 = 15584

Input: N = 5, D = 487
Output: 981792

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The idea is to compute the value of F(2) to F(N) iteratively with the help of the loop. Also, the maximum and minimum digits in each number can be computed using the help of the loop by dividing the number by 10, Simultaneously taking the modulo to get the digit.

Below is the implementation of the above approach:

 `// C++ implementation to find the value ` `// of the given function for the value ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to find minimum digit ` `// in the decimal representation of N ` `int` `MIN(``int` `n) ` `{ ` `    ``int` `ans = 11; ` ` `  `    ``// Loop to find the minimum ` `    ``// digit in the number ` `    ``while` `(n) { ` `        ``ans = min(ans, n % 10); ` `        ``n /= 10; ` `    ``} ` `    ``return` `ans; ` `} ` ` `  `// Function to find maximum digit ` `// in the decimal representation of N ` `int` `MAX(``int` `n) ` `{ ` `    ``int` `ans = -1; ` ` `  `    ``// Loop to find the maximum ` `    ``// digit in the number ` `    ``while` `(n) { ` `        ``ans = max(ans, n % 10); ` `        ``n /= 10; ` `    ``} ` `    ``return` `ans; ` `} ` ` `  `// Function to find the value ` `// of the given function ` `void` `Find_value(``int` `n, ``int` `k) ` `{ ` `    ``k--; ` `    ``int` `x = 0; ` `    ``int` `y = 0; ` ` `  `    ``// Loop to compute the values ` `    ``// of the given number ` `    ``while` `(k--) { ` `        ``x = MIN(n); ` `        ``y = MAX(n); ` ` `  `        ``if` `(y - x == 0) ` `            ``break``; ` `        ``n *= (y - x); ` `    ``} ` `    ``cout << n; ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `N = 487, D = 5; ` ` `  `    ``// Function Call ` `    ``Find_value(N, D); ` ` `  `    ``return` `0; ` `} `

 `// Java implementation to find the value ` `// of the given function for the value ` ` `  `class` `GFG{ ` ` `  `// Function to find minimum digit in ` `// the decimal representation of N ` `static` `int` `MIN(``int` `n) ` `{ ` `    ``int` `ans = ``11``; ` ` `  `    ``// Loop to find the minimum ` `    ``// digit in the number ` `    ``while` `(n > ``0``) ` `    ``{ ` `        ``ans = Math.min(ans, n % ``10``); ` `        ``n /= ``10``; ` `    ``} ` `    ``return` `ans; ` `} ` ` `  `// Function to find maximum digit ` `// in the decimal representation of N ` `static` `int` `MAX(``int` `n) ` `{ ` `    ``int` `ans = -``1``; ` ` `  `    ``// Loop to find the maximum ` `    ``// digit in the number ` `    ``while` `(n > ``0``)  ` `    ``{ ` `        ``ans = Math.max(ans, n % ``10``); ` `        ``n /= ``10``; ` `    ``} ` `    ``return` `ans; ` `} ` ` `  `// Function to find the value ` `// of the given function ` `static` `void` `Find_value(``int` `n, ``int` `k) ` `{ ` `    ``k--; ` `    ``int` `x = ``0``; ` `    ``int` `y = ``0``; ` ` `  `    ``// Loop to compute the values ` `    ``// of the given number ` `    ``while` `(k-- > ``0``) ` `    ``{ ` `        ``x = MIN(n); ` `        ``y = MAX(n); ` ` `  `        ``if` `(y - x == ``0``) ` `            ``break``; ` `        ``n *= (y - x); ` `    ``} ` `    ``System.out.print(n); ` `} ` ` `  `// Driver Code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `N = ``487``, D = ``5``; ` ` `  `    ``// Function Call ` `    ``Find_value(N, D); ` `} ` `} ` ` `  `// This code is contributed by 29AjayKumar `

 `# Python3 implementation to find the value ` `# of the given function for the value ` ` `  `# Function to find minimum digit ` `# in the decimal representation of N ` `def` `MIN``(n): ` `     `  `    ``ans ``=` `11` `     `  `    ``# Loop to find the minimum ` `    ``# digit in the number ` `    ``while` `n: ` `        ``ans ``=` `min``(ans, n ``%` `10``) ` `        ``n ``/``/``=` `10` `    ``return` `ans ` ` `  `# Function to find maximum digit in  ` `# the decimal representation of N ` `def` `MAX``(n): ` `     `  `    ``ans ``=` `-``1` `     `  `    ``# Loop to find the maximum ` `    ``# digit in the number ` `    ``while` `n: ` `        ``ans ``=` `max``(ans, n ``%` `10``) ` `        ``n ``/``/``=` `10` `    ``return` `ans ` ` `  `# Function to find the value ` `# of the given function ` `def` `Find_value(n, k): ` `     `  `    ``k ``-``=` `1` `    ``(x, y) ``=` `(``0``, ``0``) ` `     `  `    ``# Loop to compute the values ` `    ``# of the given number ` `    ``while` `k: ` `        ``k ``-``=` `1` `        ``x ``=` `MIN``(n) ` `        ``y ``=` `MAX``(n) ` `        ``if` `((y ``-` `x) ``=``=` `0``): ` `            ``break` `        ``n ``*``=` `(y ``-` `x) ` `         `  `    ``print``(n, end ``=` `' '``) ` ` `  `# Driver Code ` `if` `__name__``=``=``'__main__'``: ` `     `  `    ``(N, D) ``=` `(``487``, ``5``) ` `     `  `    ``# Function Call ` `    ``Find_value(N, D) ` ` `  `# This code is contributed by rutvik_56 `

 `// C# implementation to find the value ` `// of the given function for the value ` `using` `System; ` ` `  `class` `GFG{ ` ` `  `// Function to find minimum digit in ` `// the decimal representation of N ` `static` `int` `MIN(``int` `n) ` `{ ` `    ``int` `ans = 11; ` ` `  `    ``// Loop to find the minimum ` `    ``// digit in the number ` `    ``while` `(n > 0) ` `    ``{ ` `        ``ans = Math.Min(ans, n % 10); ` `        ``n /= 10; ` `    ``} ` `    ``return` `ans; ` `} ` ` `  `// Function to find maximum digit ` `// in the decimal representation of N ` `static` `int` `MAX(``int` `n) ` `{ ` `    ``int` `ans = -1; ` ` `  `    ``// Loop to find the maximum ` `    ``// digit in the number ` `    ``while` `(n > 0)  ` `    ``{ ` `        ``ans = Math.Max(ans, n % 10); ` `        ``n /= 10; ` `    ``} ` `    ``return` `ans; ` `} ` ` `  `// Function to find the value ` `// of the given function ` `static` `void` `Find_value(``int` `n, ``int` `k) ` `{ ` `    ``k--; ` `    ``int` `x = 0; ` `    ``int` `y = 0; ` ` `  `    ``// Loop to compute the values ` `    ``// of the given number ` `    ``while` `(k-- > 0) ` `    ``{ ` `        ``x = MIN(n); ` `        ``y = MAX(n); ` ` `  `        ``if` `(y - x == 0) ` `            ``break``; ` `        ``n *= (y - x); ` `    ``} ` `    ``Console.Write(n); ` `} ` ` `  `// Driver Code ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``int` `N = 487, D = 5; ` ` `  `    ``// Function Call ` `    ``Find_value(N, D); ` `} ` `} ` ` `  `// This code is contributed by 29AjayKumar `

Output:
```981792
```

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Improved By : 29AjayKumar, rutvik_56

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