The fs.mkdirSync() method is an inbuilt application programming interface of fs module which provides an API for interacting with the file system in a manner closely modeled around standard POSIX functions.
The fs.mkdirSync() method is used to create a directory Synchronously.
Syntax:
fs.mkdirSync( path, options )
Parameters: This method accept two parameters as mentioned above and described below:
- path: The path at which directory is to be created. It can be string, buffer, etc.
- options: It is an optional parameter which determines how to create directory like recursively, etc.
Return value: It returns undefined.
Below examples illustrate the use of fs.mkdirSync() method in Node.js:
Example 1:
// Node.js program to demonstrate the // fs.mkdirSync() method const fs = require( "fs" );
const path = require( "path" );
// Using fs.exists() method to // check that the directory exists or not console.log( "Checking for directory " + path.join(__dirname, "Geeks" ));
fs.exists(path.join(__dirname, "Geeks" ), exists => {
console.log(exists ? "The directory already exists" : "Not found!" );
}); // Using fs.mkdirSync() method // to create the directory fs.mkdirSync(path.join(__dirname, "Geeks" ));
// Using fs.exists() method to // check that the directory exists or not fs.exists(path.join(__dirname, "Geeks" ), exists => {
console.log(exists ? "The directory already exists" : "Not found!" );
}); |
Output:
Checking for directory c:\Users\Suraj\node\Geeks Not found! The directory already exists
Example 2:
// Node.js program to demonstrate the // fs.mkdirSync() method const fs = require( "fs" );
const path = require( "path" );
// Using fs.exists() method to // check that the directory exists or not console.log( "Checking for directory" + path.join(__dirname, "Tisu" ));
fs.exists(path.join(__dirname, "Tisu" ), exists => {
console.log(exists ? "The directory already exists"
: "Not found!" );
}); // Using fs.mkdirSync() method // to create the directory recursively fs.mkdirSync(path.join(__dirname, "Tisu" ), true );
// Using fs.exists() method to // check that the directory exists or not fs.exists(path.join(__dirname, "Tisu" ), exists => {
console.log(exists ? "The directory already exists" : "Not found!" );
}); |
Output:
Checking for directory c:\Users\Suraj\node\Tisu Not found! The directory already exists
Note: The above program will compile and run by using the node index.js
command.
Reference: https://nodejs.org/api/fs.html#fs_fs_mkdirsync_path_options