Given two strings S and N of the same length, consisting of alphabetical and numeric characters respectively, the task is to generate a new string obtained by adding the integer value of each character of string N with the ASCII value of the same indexed character of string S. Finally, print the resultant string.
Note: If the sum exceeds 122, then subtract 26 from the sum and print the resultant character.
Examples:
Input: S = “sun”, N = “966”
Output: “bat”
Explanation:
ASCII value of ‘s’ = 115.
Therefore, 115 + 9 = 124 – 26 = 98. Therefore, equivalent character is’b’.
ASCII value of ‘u’ = 117.
Therefore, 117 + 6 = 123 – 26 = 97. Therefore, equivalent character is ‘a’.
ASCII value of ‘n’ = 110.
Therefore, 110 + 6 = 116. Therefore, equivalent character is ‘t’.Input: S = “apple”, N = “12580”
Output: “brute”
Approach: Follow the steps below to solve the problem:
-
Traverse the string S:
- Convert the current character of string N to its equivalent integer value.
- Add the obtained integer value to the equivalent ASCII value of the current character in string S.
- If the value exceeds 122, which is the ASCII value of the last alphabet ‘z’, then subtract the value by 26.
- Update string S by replacing a current character with the character whose ASCII value is equal to the value obtained.
- Print the resultant string after completing the above steps.
Below is the implementation of the above approach:
// C++ program for the above approach #include <bits/stdc++.h> using namespace std;
// Function to modify a given string // by adding ASCII value of characters // from a string S to integer values of // same indexed characters in string N void addASCII(string S, string N)
{ // Traverse the string
for ( int i = 0; i < S.size(); i++) {
// Stores integer value of
// character in string N
int a = int (N[i]) - '0' ;
// Stores ASCII value of
// character in string S
int b = int (S[i]) + a;
// If b exceeds 122
if (b > 122)
b -= 26;
// Replace the character
S[i] = char (b);
}
// Print resultant string
cout << S;
} // Driver Code int main()
{ // Given strings
string S = "sun" , N = "966" ;
// Function call to modify
// string S by given operations
addASCII(S, N);
return 0;
} |
// Java program for the above approach import java.util.*;
class GFG
{ // Function to modify a given String // by adding ASCII value of characters // from a String S to integer values of // same indexed characters in String N static void addASCII( char []S, char []N)
{ // Traverse the String
for ( int i = 0 ; i < S.length; i++)
{
// Stores integer value of
// character in String N
int a = ( int )(N[i]) - '0' ;
// Stores ASCII value of
// character in String S
int b = ( int )(S[i]) + a;
// If b exceeds 122
if (b > 122 )
b -= 26 ;
// Replace the character
S[i] = ( char )(b);
}
// Print resultant String
System.out.print(S);
} // Driver Code public static void main(String[] args)
{ // Given Strings
String S = "sun" , N = "966" ;
// Function call to modify
// String S by given operations
addASCII(S.toCharArray(), N.toCharArray());
} } // This code is contributed by shikhasingrajput. |
# python 3 program for the above approach # Function to modify a given string # by adding ASCII value of characters # from a string S to integer values of # same indexed characters in string N def addASCII(S, N):
# Traverse the string
for i in range ( len (S)):
# Stores integer value of
# character in string N
a = ord (N[i]) - ord ( '0' )
# Stores ASCII value of
# character in string S
b = ord (S[i]) + a
# If b exceeds 122
if (b > 122 ):
b - = 26
# Replace the character
S = S.replace(S[i], chr (b))
# Print resultant string
print (S)
# Driver Code if __name__ = = "__main__" :
# Given strings
S = "sun"
N = "966"
# Function call to modify
# string S by given operations
addASCII(S, N)
# This code is contributed by ukasp.
|
// C# program for the above approach using System;
public class GFG
{ // Function to modify a given String // by adding ASCII value of characters // from a String S to integer values of // same indexed characters in String N static void addASCII( char []S, char []N)
{ // Traverse the String
for ( int i = 0; i < S.Length; i++)
{
// Stores integer value of
// character in String N
int a = ( int )(N[i]) - '0' ;
// Stores ASCII value of
// character in String S
int b = ( int )(S[i]) + a;
// If b exceeds 122
if (b > 122)
b -= 26;
// Replace the character
S[i] = ( char )(b);
}
// Print resultant String
Console.Write(S);
} // Driver Code public static void Main(String[] args)
{ // Given Strings
String S = "sun" , N = "966" ;
// Function call to modify
// String S by given operations
addASCII(S.ToCharArray(), N.ToCharArray());
} } // This code is contributed by shikhasingrajput |
<script> // JavaScript program for the above approach
// Function to modify a given string
// by adding ASCII value of characters
// from a string S to integer values of
// same indexed characters in string N
function addASCII(S, N) {
var newStr = new Array(S.length);
// Traverse the string
for ( var i = 0; i < S.length; i++) {
// Stores integer value of
// character in string N
var a = N[i].charCodeAt(0) - "0" .charCodeAt(0);
// Stores ASCII value of
// character in string S
var b = S[i].charCodeAt(0) + a;
// If b exceeds 122
if (b > 122) b -= 26;
// Replace the character
newStr[i] = String.fromCharCode(b);
}
// Print resultant string
document.write(newStr.join( "" ));
}
// Driver Code
// Given strings
var S = "sun" ,
N = "966" ;
// Function call to modify
// string S by given operations
addASCII(S, N);
</script>
|
bat
Time Complexity: O(|S|)
Auxiliary Space: O(1)