Open In App

Java Program to Find Maximum value possible by rotating digits of a given number

Given a positive integer N, the task is to find the maximum value among all the rotations of the digits of the integer N.

Examples:



Input: N = 657
Output: 765
Explanation: All rotations of 657 are {657, 576, 765}. The maximum value among all these rotations is 765.

Input: N = 7092
Output: 9270
Explanation:
All rotations of 7092 are {7092, 2709, 9270, 0927}. The maximum value among all these rotations is 9270.



Approach: The idea is to find all rotations of the number N and print the maximum among all the numbers generated. Follow the steps below to solve the problem:

Below is the implementation of the above approach:




// Java program for the above approach
import java.util.*;
class GFG
{
  
// Function to find the maximum value
// possible by rotations of digits of N
static void findLargestRotation(int num)
{
    
    // Store the required result
    int ans = num;
  
    // Store the number of digits
    int len = (int)Math.floor(((int)Math.log10(num)) + 1);
    int x = (int)Math.pow(10, len - 1);
  
    // Iterate over the range[1, len-1]
    for (int i = 1; i < len; i++) {
  
        // Store the unit's digit
        int lastDigit = num % 10;
  
        // Store the remaining number
        num = num / 10;
  
        // Find the next rotation
        num += (lastDigit * x);
  
        // If the current rotation is
        // greater than the overall
        // answer, then update answer
        if (num > ans) {
            ans = num;
        }
    }
  
    // Print the result
    System.out.print(ans);
}
  
// Driver Code
public static void main(String[] args)
{
    int N = 657;
    findLargestRotation(N);
}
}
  
// This code is contributed by sanjoy_62.

Output: 
765

 

Time Complexity: O(log10N)
Auxiliary Space: O(1)

Please refer complete article on Maximum value possible by rotating digits of a given number for more details!


Article Tags :