ISRO | ISRO CS 2017 – May | Question 2

If A and B be two arbitrary events, then
(A) P(A ∩ B) = P(A)P(B)
(B) P(A ∪ B) = P(A) + P(B)
(C) P(A / B) = P(A ∩ B) + P(B)
(D) P(A ∪ B) Answer: (D)
Explanation: Case:1 P(A ∪ B) = P(A) + P(B) – P (A ∩ B).
Case:2 For two mutually exclusive events, (A ∩ B) = 0, So P(A ∪ B) Quiz of this Question