Consider a 50 kbps satellite channel with a 500 milliseconds round trip propagation delay. If the sender wants to transmit 1000-bit frames, how much time will it take for the receiver to receive the frame?
(A) 250 milliseconds
(B) 20 milliseconds
(C) 520 milliseconds
(D) 270 milliseconds
Answer:
The correct answer is (D).
Explanation:
Given,
Bandwidth = 50 kbps
Round Trip time = 500 milliseconds = 2 * propagation time
So, propagation time = 250 ms
Transmission Time = data size / bandwidth = 1000 bits / 50 kbps = 20 ms
Hence, Time Taken by receiver to receive the frame ==> 250 ms + 20 ms = 270 ms.
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