In a system an RSA algorithm with p=5 and q=11, is implemented for data security. What is the value of the decryption key if the value of the encryption key is 27?
(A) 3
(B) 7
(C) 27
(D) 40
Answer: (A)
Explanation: p = 5 and q = 11, encryption key, e = 27
n = p * q = 5 * 11 = 55 z = (p-1) * (q-1) = 4 * 10 = 40
Let the value of decryption key be ‘d’ such that:
e * d mod z = 1 27 * d mod 40 = 1 d = 3
So, the correct answer is (A)
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