If (|x| – 3) (|y| + 4) = 12. Then number of pairs of integers (x, y) satisfy this equation ?
(A) 4
(B) 10
(C) 6
(D) 8
Answer: (B)
Explanation: Product of two integers is 12. Further |y| + 4 ±4. So, we know that one of the numbers has to be greater than 4.
So, we can have,
1 x 12 => x = ±4, y = +8 2 x 6 => x = ±5, y = +2 3 x 4 => x = ±6, y = 0 4 + 4 + 2 = 10
So, there 10 possible solutions.
Option (B) is correct.
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