Consider the situation in which the disk read/write head is currently located at track 45 (of tracks 0-255) and moving in the positive direction. Assume that the following track requests have been made in this order: 40, 67, 11, 240, 87. What is the order in which optimised C-SCAN would service these requests and what is the total seek distance?
(A) 600
(B) 810
(C) 505
(D) 550
Answer: (C)
Explanation: Circular scanning works just like the elevator to some extent. It begins its scan toward the nearest end and works it way all the way to the end of the system. Once it hits the bottom or top it jumps to the other end and moves in the same direction. Keep in mind that the huge jump doesn’t count as a head movement.
Solution:
Disk queue: 40, 67, 11, 240, 87 and disk is currently located at track 45.The order in which optimised C-SCAN would service these requests is shown by the following diagram.
Total seek distance=(67-45)+(87-67)+(240-87)+(255-240)+(255-0)+(11-0)+(40-11)
=22+20+153+15+255+11+29 =505
Option (C) is the correct answer.
Reference:
http://www.cs.iit.edu/~cs561/cs450/disksched/disksched.html
http://iete-elan.ac.in/SolQP/soln/DC14_sol.pdf
This solution is contributed by Nitika Bansal
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