Which one of the following options is CORRECT given three positive integers x, y and z, and a predicate?
P(x) = ¬(x=1)∧∀y(∃z(x=y*z)⇒(y=x)∨(y=1))
(A)
P(x) being true means that x is a number other than 1
(B)
P(x) is always true irrespective of the value of x
(C)
P(x) being true means that x has exactly two factors other than 1 and x
(D)
P(x) being true means that x is a prime number
Answer: (D)
Explanation:
The predicate is evaluated as
P(x) = (¬(x=1))∧(∀y(∃z(x=y*z)⇒((y=x)∨(y=1))))
P(x) being true means x ≠ 1 and
For all y if there exists a z such that x = y*z then
y must be x (i.e. z=1) or y must be 1 (i.e. z=x)
It means that x have only two factors first is 1
and second is x itself.
This predicate defines the prime number. Quiz of this Question
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