GATE | CS 2022 | Question 22

What is printed by the following ANSI C program? 

#include<stdio.h> 
int main(int argc, char *argv[]) 
{ 
   int x = 1, z[2] = {10, 11}; 
   int *p = NULL; 
   p = &x; 
   *p = 10; 
   p = &z[1]; 
   *(&z[0] + 1) += 3; 
   printf("%d, %d, %d\n", x, z[0], z[1]); 
   return 0; 
}

(A)

1, 10, 11 

(B)

1, 10, 14 

(C)

10, 14, 11

(D)

10, 10, 14 

Answer: (D)
Explanation:

From the C-programming code, x=1, z[0]=10 and z[1]=11

int *p= NULL; p=&x;

*p=10;

After this is executed, we are modifying the value of the variable ‘x’ and it’s value gets modified as x=10.

*(&z[0]+1)+=3;

The above line means,

*( address of z[0]+1 ) += 3

=>*( address of z[1] ) += 3

=>z[1] += 3 ==> z[1] = z[1] + 3

=>z[1]=14

It is clear that the value of z[0] is not modified. So, option D is the correct answer. 

Quiz of this Question
Please comment below if you find anything wrong in the above post