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Find the probability of getting a number less than 5 in a single dice throw

A branch of mathematics that deals with the happening of a random event is termed probability. It is used in Maths to predict how likely events are to happen.

The probability of any event can only be between 0 and 1 and it can also be written in the form of a percentage.



The probability of event A is generally written as P(A).

Here P represents the possibility and A represents the event. It states how likely an event is about to happen. The probability of an event can exist only between 0 and 1 where 0 indicates that event is not going to happen i.e. Impossibility and 1 indicates that it is going to happen for sure i.e. Certainty



If we are not sure about the outcome of an event, we take help of the probabilities of certain outcomes—how likely they occur. For a proper understanding of probability we take an example as tossing a coin:

There will be two possible outcomes—heads or tails.

The probability of getting heads is half. You might already know that the probability is half/half or 50% as the event is an equally likely event and is complementary so the possibility of getting heads or tails is 50%.

Formula of Probability

Probability of an event, P(A) = Favorable outcomes / Total number of outcomes

Some Terms of Probability Theory

Some Probability Formulas

Addition rule: Union of two events, say A and B, then

P(A or B) = P(A) + P(B) – P(A∩B)

P(A ∪ B) = P(A) + P(B) – P(A∩B)

Complementary rule: If there are two possible events of an experiment so the probability of one event will be the Complement of another event. For example – if A and B are two possible events, then

P(B) = 1 – P(A) or P(A’) = 1 – P(A).

P(A) + P(A′) = 1.

Conditional rule: When the probability of an event is given and the second is required for which first is given, then

P(B, given A) = P(A and B), P(A, given B). It can be vice versa

P(B∣A) = P(A∩B)/P(A)

Multiplication rule: Intersection of two other events i.e. events A and B need to occur simultaneously. Then

P(A and B) = P(A)⋅P(B).

P(A∩B) = P(A)⋅P(B∣A)

Find the probability of getting a number less than 5 in a single dice throw.

Solution : 

When the dice is rolled then there will be 6 outcomes.

Total number of favorable outcome { set of outcome } = {1, 2, 3, 4, 5, 6 }

                                                                                    = 6 

Now as per the question 

Probability of getting a number less than 5 in a single throw is 4 

Numbers less than 5 are { 1,2,3,4}

therefore favorable outcome will be = 4

                                                 P(A) = Favorable outcomes / Total number of outcomes

                                                        = 4/6

                                                        = 2/3

Hence the probability of getting a number less than 5 in a single throw of a die  is 2/3

Similar Questions

Question 1: Find the probability of getting a number less than 4 in a single throw of a die. 

Solution: 

When the dice is rolled then there will be 6 outcomes

Total number of favorable outcome { set of outcome } = {1 ,2 ,3 ,4 , 5, 6 }

                                                                                       = 6

Now as per the question

probability of getting a number less than 4 in a single throw is 3

Numbers less than 4 are { 1,2,3}

Therefore favorable outcome will be = 3

P(A) = Favorable outcomes / Total number of outcomes

        = 3/6

        = 1/2

Hence the probability of getting a number less than 4 in a single throw of a die is 1/2

Question 2: Find the probability of getting a number more than 4 in a single throw of a die.

Solution:

When the dice is rolled then there will be 6 outcomes.

Total number of favorable outcome { set of outcome } = {1 ,2 ,3 ,4 , 5, 6 }

                                                                                    = 6

Now as per the question

probability of getting a number more than 4 in a single throw is 2

Numbers more than 4 are { 5,6}

Therefore favorable outcome will be = 2

P(A) = Favorable outcomes / Total number of outcomes

        = 2/6

        = 1/3

Hence the probability of getting a number more than 4 in a single throw of a die is 1/3

Question 3: Find the probability of getting a number 5 in a single throw of a die.

Solution:

When the dice is rolled then there will be 6 outcomes.

Total number of favorable outcome { set of outcome } = {1 ,2 ,3 ,4 , 5, 6 }

                                                                                    = 6

Now as per the question

probability of getting a number 5 in a single throw is 1

Therefore favorable outcome will be = 1

P(A) = Favorable outcomes / Total number of outcomes

        = 1/6

Hence the probability of getting a number 5 in a single throw of a die is 1/6

Question 4: What is the chance of rolling a 3 two times in a row?

Solution:

P(A) = Favorable outcomes / Total number of outcomes

Probability of getting 3 = 1/6.

Rolling dice is an independent event, it is not dependent on how many times it’s been rolled.

Probability of getting 3 two times in a row = probability of getting 3 first time × probability of getting 3 second time.

Probability of getting 3 two times in a row  = (1/6) × (1/6) = 1/36.

Hence, the probability of getting 3 two times in a row 2.77 %.


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