The d3.utcYears() function in D3.js is used to return all the years with date in the given range of start and end date in Coordinated Universal Time (UTC).
Syntax:
d3.utcYears(start, end, step);
Parameters: This function accept three parameters which are given below:
- Start: This parameter holds the given start date.
- end: This parameter holds the given end date.
- step: It is the optional parameter which holds the value used to skip years.
Return Value: This function returns all the possible years in the given range.
Below programs illustrate the d3.utcYears() function in D3.js:
Example 1:
<!DOCTYPE html> <html> <head>
<title>
D3.js | d3.utcYears() Function
</title>
<script src =
</script>
</head>
<body>
<script>
// Initialising start and end date
var start = new Date(2015, 01, 01);
var end = new Date(2020, 01, 01);
// Calling the utcYears() function
// without step value
var a = d3.utcYears(start, end);
// Getting the years values
console.log(a);
</script>
</body>
</html> |
Output:
["2016-01-01T00:00:00.000Z", "2017-01-01T00:00:00.000Z", "2018-01-01T00:00:00.000Z", "2019-01-01T00:00:00.000Z", "2020-01-01T00:00:00.000Z"]
Example 2:
<!DOCTYPE html> <html> <head>
<title>
D3.js | d3.utcYears() Function
</title>
<script src =
</script>
</head>
<body>
<script>
// Initialising start and end date
var start = new Date(2015, 01, 01);
var end = new Date(2020, 01, 01);
// Calling the utcYears() function
// with step value
var a = d3.utcYears(start, end, 2);
// Getting the years values
console.log(a);
</script>
</body>
</html> |
Output:
["2016-01-01T00:00:00.000Z", "2018-01-01T00:00:00.000Z", "2020-01-01T00:00:00.000Z"]
Reference: https://devdocs.io/d3~5/d3-time#timeYears