Open In App

D3.js | d3.timeThursdays() Function

The d3.timeThursdays() function in D3.js is used to return all the dates based on Thursday in the given range of start and end date.

Syntax:



d3.timeThursdays( start, end, step );

Parameters: This function accept three parameters which are given below:

Return Value: This function returns all the dates based on Thursday.



Below programs illustrate the d3.timeThursdays() function in D3.js:

Example 1:




<!DOCTYPE html>
<html>
  
<head>
    <title>
        D3.js | d3.timeThursdays() Function
    </title>
      
    <script src = 
        "https://d3js.org/d3.v4.min.js">
    </script>
</head>
  
<body>
    <script>
          
        // Initialising start and end date
        var start = new Date(2015, 07, 01);
        var end = new Date(2015, 07, 30);
          
        // Calling the timeThursdays() function
        // without step value
        var a = d3.timeThursdays(start, end);
          
        // Getting the Thursday dates
        console.log(a);
    </script>
</body>
  
</html>                    

Output:

["2015-08-05T18:30:00.000Z", "2015-08-12T18:30:00.000Z", 
"2015-08-19T18:30:00.000Z", "2015-08-26T18:30:00.000Z"]

Example 2:




<!DOCTYPE html>
<html>
  
<head>
    <title>
        D3.js | d3.timeThursdays() Function
    </title>
      
    <script src = 
        "https://d3js.org/d3.v4.min.js">
    </script>
</head>
  
<body>
    <script>
          
        // Initialising start and end date
         var start = new Date(2015, 07, 01);
         var end = new Date(2015, 07, 30);
            
         // Calling the timeThursdays() function
         // with step value
         var a = d3.timeThursdays(start, end, 2);
            
         // Getting the Thursday dates
         console.log(a);
    </script>
</body>
  
</html>                    

Output:

["2015-08-05T18:30:00.000Z", "2015-08-19T18:30:00.000Z"]

Reference: https://devdocs.io/d3~5/d3-time#timeThursdays


Article Tags :