The set.remove() is a function in D3.js. If the given array contains the specified value then removes it and returns true. Otherwise, this function does nothing and returns false.
Syntax:
d3.set([Array]).remove(element);
Parameters: This function accepts two parameters which are illustrated below:
- Array: This is an given array of elements as string.
- element: This is the value which is going to be searched into the given array and removes it if present and returns true otherwise does nothing and returns false.
Return Value: It returns true if the given array contains the specified value Otherwise, returns false.
Note: It does not hold the updated array.
Below programs illustrate the d3.set.remove() function in D3.js.
Example 1:
<!DOCTYPE html> <html> <head> <title> d3.set.remove() Function</title>
</head> <body> <script>
// Initialising an array
Array1 = ["a", "a", "b", "c"];
Array2 = ["c", "c", "c"];
Array3 = ["Geeks", "gfg", "GeeksforGeeks"];
// Calling the d3.set.remove() function
A = d3.set(Array1).remove("a");
B = d3.set(Array2).remove("a");
C = d3.set(Array3).remove("Geeks");
// Getting the value true if the specified element
// is present in the array otherwise false
console.log(A);
console.log(B);
console.log(C);
</script>
</body> |
Output:
true false true
Example 2:
<!DOCTYPE html> <html> <head> <title> d3.set.remove() Function</title>
</head> <body> <script>
// Calling the d3.set.remove() function
// with a array and a element as the parameter
A = d3.set([1, 2, 3, 3]).remove(4);
B = d3.set(["a"]).remove("a");
C = d3.set(["a", "b", "c", "a", "b", "c"]).remove("d");
// Getting the value true if the specified element
// is present in the array otherwise false
console.log(A);
console.log(B);
console.log(C);
</script>
</body> |
Output:
false true false
Ref: https://devdocs.io/d3~5/d3-collection#set_remove