# Count of possible subarrays and subsequences using given length of Array

Given an integer N which denotes the length of an array, the task is to count the number of subarray and subsequence possible with the given length of the array.

Examples:

Input: N = 5
Output:
Count of subarray = 15
Count of subsequence = 32

Input: N = 3
Output:
Count of subarray = 6
Count of subsequence = 8

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The key observation fact for the count of the subarray is the number of ends position possible for each index elements of the array can be (N – i), Therefore the count of the subarray for an array of size N can be:

```Count of Sub-arrays = (N) * (N + 1)
---------------
2
```

The key observation fact for the count of the subsequence possible is each element of the array can be included in a subsequence or not. Therefore, the choice for each element is 2.

`Count of subsequences = 2N`

Below is the implementation of the above approach:

 `// C++ implementation to count ` `// the subarray and subsequence of ` `// given length of the array ` `#include ` `using` `namespace` `std; ` ` `  `// Function to count the subarray ` `// for the given array ` `int` `countSubarray(``int` `n){ ` `    ``return` `((n)*(n + 1))/2; ` `} ` ` `  `// Function to count the subsequence ` `// for the given array length ` `int` `countSubsequence(``int` `n){ ` `    ``return` `pow``(2, n); ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `n = 5; ` `    ``cout << (countSubarray(n)) << endl; ` `    ``cout << (countSubsequence(n)) << endl; ` `    ``return` `0; ` `} ` ` `  `// This code is contributed by mohit kumar 29 `

 `// Java implementation to count ` `// the subarray and subsequence of ` `// given length of the array ` `class` `GFG{ ` `  `  `// Function to count the subarray ` `// for the given array ` `static` `int` `countSubarray(``int` `n){ ` `    ``return` `((n)*(n + ``1``))/``2``; ` `} ` `  `  `// Function to count the subsequence ` `// for the given array length ` `static` `int` `countSubsequence(``int` `n){ ` `    ``return` `(``int``) Math.pow(``2``, n); ` `} ` `  `  `// Driver Code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `n = ``5``; ` `    ``System.out.print((countSubarray(n)) +``"\n"``); ` `    ``System.out.print((countSubsequence(n)) +``"\n"``); ` `} ` `} ` `  `  `// This code is contributed by Princi Singh `

 `# Python implementation to count ` `# the subarray and subsequence of ` `# given length of the array ` ` `  `# Function to count the subarray ` `# for the given array  ` `def` `countSubarray(n): ` `    ``return` `((n)``*``(n ``+` `1``))``/``/``2` `     `  `# Function to count the subsequence ` `# for the given array length ` `def` `countSubsequence(n): ` `    ``return` `(``2``*``*``n) ` ` `  `# Driver Code     ` `if` `__name__ ``=``=` `"__main__"``: ` `    ``n ``=` `5` `    ``print``(countSubarray(n)) ` `    ``print``(countSubsequence(n)) `

 `// C# implementation to count ` `// the subarray and subsequence of ` `// given length of the array ` `using` `System; ` ` `  `class` `GFG{ ` `   `  `// Function to count the subarray ` `// for the given array ` `static` `int` `countSubarray(``int` `n){ ` `    ``return` `((n)*(n + 1))/2; ` `} ` `   `  `// Function to count the subsequence ` `// for the given array length ` `static` `int` `countSubsequence(``int` `n){ ` `    ``return` `(``int``) Math.Pow(2, n); ` `} ` `   `  `// Driver Code ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``int` `n = 5; ` `    ``Console.Write((countSubarray(n)) +``"\n"``); ` `    ``Console.Write((countSubsequence(n)) +``"\n"``); ` `} ` `} ` ` `  `// This code is contributed by Rajput-Ji `

Output:
```15
32
```

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