Given a Binary Tree, convert it into a Doubly Linked List where the nodes are represented Spirally. The left pointer of the binary tree node should act as a previous node for created DLL and the right pointer should act as the next node.
The solution should not allocate extra memory for DLL nodes. It should use binary tree nodes for creating DLL i.e. only change of pointers is allowed.
For example, for the tree on the left side, Doubly Linked List can be,
1 2 3 7 6 5 4 8 9 10 11 13 14 or
1 3 2 4 5 6 7 14 13 11 10 9 8.
We strongly recommend you minimize your browser and try this yourself first.
We can do this by doing a spiral order traversal in O(n) time and O(n) extra space. The idea is to use deque (Double-ended queue) that can be expanded or contracted on both ends (either its front or it’s back). We do something similar to level order traversal but to maintain spiral order, for every odd level, we dequeue node from the front and insert its left and right children in the back of the deque data structure. And for each even level, we dequeue node from the back and insert its right and left children in the front of the deque. We also maintain a stack to store Binary Tree nodes. Whenever we pop nodes from deque, we push that node into the stack.
Later, we pop all nodes from the stack and push the nodes at the beginning of the list. We can avoid the use of stack if we maintain a tail pointer that always points to the last node of DLL and inserts nodes in O(1) time in the end.
Below is the implementation of the above idea
/* c++ program to convert Binary Tree into Doubly Linked List where the nodes are represented
spirally. */
#include <bits/stdc++.h> using namespace std;
// A Binary Tree Node struct Node
{ int data;
struct Node *left, *right;
}; /* Given a reference to the head of a list and a node, inserts the node on the front of the list. */ void push(Node** head_ref, Node* node)
{ // Make right of given node as head and left as
// NULL
node->right = (*head_ref);
node->left = NULL;
// change left of head node to given node
if ((*head_ref) != NULL)
(*head_ref)->left = node ;
// move the head to point to the given node
(*head_ref) = node;
} // Function to prints contents of DLL void printList(Node *node)
{ while (node != NULL)
{
cout << node->data << " " ;
node = node->right;
}
} /* Function to print corner node at each level */ void spiralLevelOrder(Node *root)
{ // Base Case
if (root == NULL)
return ;
// Create an empty deque for doing spiral
// level order traversal and enqueue root
deque<Node*> q;
q.push_front(root);
// create a stack to store Binary Tree nodes
// to insert into DLL later
stack<Node*> stk;
int level = 0;
while (!q.empty())
{
// nodeCount indicates number of Nodes
// at current level.
int nodeCount = q.size();
// Dequeue all Nodes of current level and
// Enqueue all Nodes of next level
if (level&1) //odd level
{
while (nodeCount > 0)
{
// dequeue node from front & push it to
// stack
Node *node = q.front();
q.pop_front();
stk.push(node);
// insert its left and right children
// in the back of the deque
if (node->left != NULL)
q.push_back(node->left);
if (node->right != NULL)
q.push_back(node->right);
nodeCount--;
}
}
else //even level
{
while (nodeCount > 0)
{
// dequeue node from the back & push it
// to stack
Node *node = q.back();
q.pop_back();
stk.push(node);
// inserts its right and left children
// in the front of the deque
if (node->right != NULL)
q.push_front(node->right);
if (node->left != NULL)
q.push_front(node->left);
nodeCount--;
}
}
level++;
}
// head pointer for DLL
Node* head = NULL;
// pop all nodes from stack and
// push them in the beginning of the list
while (!stk.empty())
{
push(&head, stk.top());
stk.pop();
}
cout << "Created DLL is:\n" ;
printList(head);
} // Utility function to create a new tree Node Node* newNode( int data)
{ Node *temp = new Node;
temp->data = data;
temp->left = temp->right = NULL;
return temp;
} // Driver program to test above functions int main()
{ // Let us create binary tree shown in above diagram
Node *root = newNode(1);
root->left = newNode(2);
root->right = newNode(3);
root->left->left = newNode(4);
root->left->right = newNode(5);
root->right->left = newNode(6);
root->right->right = newNode(7);
root->left->left->left = newNode(8);
root->left->left->right = newNode(9);
root->left->right->left = newNode(10);
root->left->right->right = newNode(11);
//root->right->left->left = newNode(12);
root->right->left->right = newNode(13);
root->right->right->left = newNode(14);
//root->right->right->right = newNode(15);
spiralLevelOrder(root);
return 0;
} |
/* Java program to convert Binary Tree into Doubly Linked List where the nodes are represented spirally */
import java.util.*;
// A binary tree node class Node
{ int data;
Node left, right;
public Node( int data)
{
this .data = data;
left = right = null ;
}
} class BinaryTree
{ Node root;
Node head;
/* Given a reference to a node,
inserts the node on the front of the list. */
void push(Node node)
{
// Make right of given node as head and left as
// NULL
node.right = head;
node.left = null ;
// change left of head node to given node
if (head != null )
head.left = node;
// move the head to point to the given node
head = node;
}
// Function to prints contents of DLL
void printList(Node node)
{
while (node != null )
{
System.out.print(node.data + " " );
node = node.right;
}
}
/* Function to print corner node at each level */
void spiralLevelOrder(Node root)
{
// Base Case
if (root == null )
return ;
// Create an empty deque for doing spiral
// level order traversal and enqueue root
Deque<Node> q = new LinkedList<Node>();
q.addFirst(root);
// create a stack to store Binary Tree nodes
// to insert into DLL later
Stack<Node> stk = new Stack<Node>();
int level = 0 ;
while (!q.isEmpty())
{
// nodeCount indicates number of Nodes
// at current level.
int nodeCount = q.size();
// Dequeue all Nodes of current level and
// Enqueue all Nodes of next level
if ((level & 1 ) % 2 != 0 ) //odd level
{
while (nodeCount > 0 )
{
// dequeue node from front & push it to
// stack
Node node = q.peekFirst();
q.pollFirst();
stk.push(node);
// insert its left and right children
// in the back of the deque
if (node.left != null )
q.addLast(node.left);
if (node.right != null )
q.addLast(node.right);
nodeCount--;
}
}
else //even level
{
while (nodeCount > 0 )
{
// dequeue node from the back & push it
// to stack
Node node = q.peekLast();
q.pollLast();
stk.push(node);
// inserts its right and left children
// in the front of the deque
if (node.right != null )
q.addFirst(node.right);
if (node.left != null )
q.addFirst(node.left);
nodeCount--;
}
}
level++;
}
// pop all nodes from stack and
// push them in the beginning of the list
while (!stk.empty())
{
push(stk.peek());
stk.pop();
}
System.out.println( "Created DLL is : " );
printList(head);
}
// Driver program to test above functions
public static void main(String[] args)
{
// Let us create binary tree as shown in above diagram
BinaryTree tree = new BinaryTree();
tree.root = new Node( 1 );
tree.root.left = new Node( 2 );
tree.root.right = new Node( 3 );
tree.root.left.left = new Node( 4 );
tree.root.left.right = new Node( 5 );
tree.root.right.left = new Node( 6 );
tree.root.right.right = new Node( 7 );
tree.root.left.left.left = new Node( 8 );
tree.root.left.left.right = new Node( 9 );
tree.root.left.right.left = new Node( 10 );
tree.root.left.right.right = new Node( 11 );
// tree.root.right.left.left = new Node(12);
tree.root.right.left.right = new Node( 13 );
tree.root.right.right.left = new Node( 14 );
// tree.root.right.right.right = new Node(15);
tree.spiralLevelOrder(tree.root);
}
} // This code has been contributed by Mayank Jaiswal(mayank_24) |
# Python3 program to convert Binary Tree # into Doubly Linked List where the nodes # are represented spirally. # Binary tree node class newNode:
# Constructor to create a newNode
def __init__( self , data):
self .data = data
self .left = None
self .right = None
""" Given a reference to the head of a list and a node, inserts the node on the front
of the list. """
def push(head_ref, node):
# Make right of given node as
# head and left as None
node.right = (head_ref)
node.left = None
# change left of head node to
# given node
if ((head_ref) ! = None ):
(head_ref).left = node
# move the head to point to
# the given node
(head_ref) = node
# Function to prints contents of DLL def printList(node):
i = 0
while (i < len (node)):
print (node[i].data, end = " " )
i + = 1
""" Function to print corner node at each level """ def spiralLevelOrder(root):
# Base Case
if (root = = None ):
return
# Create an empty deque for doing spiral
# level order traversal and enqueue root
q = []
q.append(root)
# create a stack to store Binary
# Tree nodes to insert into DLL later
stk = []
level = 0
while ( len (q)):
# nodeCount indicates number of
# Nodes at current level.
nodeCount = len (q)
# Dequeue all Nodes of current level
# and Enqueue all Nodes of next level
if (level& 1 ): # odd level
while (nodeCount > 0 ):
# dequeue node from front &
# push it to stack
node = q[ 0 ]
q.pop( 0 )
stk.append(node)
# insert its left and right children
# in the back of the deque
if (node.left ! = None ):
q.append(node.left)
if (node.right ! = None ):
q.append(node.right)
nodeCount - = 1
else : # even level
while (nodeCount > 0 ):
# dequeue node from the back &
# push it to stack
node = q[ - 1 ]
q.pop( - 1 )
stk.append(node)
# inserts its right and left
# children in the front of
# the deque
if (node.right ! = None ):
q.insert( 0 , node.right)
if (node.left ! = None ):
q.insert( 0 , node.left)
nodeCount - = 1
level + = 1
# head pointer for DLL
head = []
# pop all nodes from stack and push
# them in the beginning of the list
while ( len (stk)):
head.append(stk[ 0 ])
stk.pop( 0 )
print ( "Created DLL is:" )
printList(head)
# Driver Code if __name__ = = '__main__' :
"""Let us create Binary Tree as
shown in above example """
root = newNode( 1 )
root.left = newNode( 2 )
root.right = newNode( 3 )
root.left.left = newNode( 4 )
root.left.right = newNode( 5 )
root.right.left = newNode( 6 )
root.right.right = newNode( 7 )
root.left.left.left = newNode( 8 )
root.left.left.right = newNode( 9 )
root.left.right.left = newNode( 10 )
root.left.right.right = newNode( 11 )
#root.right.left.left = newNode(12)
root.right.left.right = newNode( 13 )
root.right.right.left = newNode( 14 )
#root.right.right.right = newNode(15)
spiralLevelOrder(root)
# This code is contributed # by SHUBHAMSINGH10 |
/* C# program to convert Binary Tree into Doubly Linked List where the nodes are represented spirally */ using System;
using System.Collections.Generic;
// A binary tree node public class Node
{ public int data;
public Node left, right;
public Node( int data)
{
this .data = data;
left = right = null ;
}
} public class BinaryTree
{ Node root;
Node head;
/* Given a reference to a node,
inserts the node on the front of the list. */
void push(Node node)
{
// Make right of given node as head and left as
// NULL
node.right = head;
node.left = null ;
// change left of head node to given node
if (head != null )
head.left = node;
// move the head to point to the given node
head = node;
}
// Function to prints contents of DLL
void printList(Node node)
{
while (node != null )
{
Console.Write(node.data + " " );
node = node.right;
}
}
/* Function to print corner node at each level */
void spiralLevelOrder(Node root)
{
// Base Case
if (root == null )
return ;
// Create an empty deque for doing spiral
// level order traversal and enqueue root
LinkedList<Node> q = new LinkedList<Node>();
q.AddFirst(root);
// create a stack to store Binary Tree nodes
// to insert into DLL later
Stack<Node> stk = new Stack<Node>();
int level = 0;
while (q.Count != 0)
{
// nodeCount indicates number of Nodes
// at current level.
int nodeCount = q.Count;
// Dequeue all Nodes of current level and
// Enqueue all Nodes of next level
if ((level & 1) % 2 != 0) //odd level
{
while (nodeCount > 0)
{
// dequeue node from front & push it to
// stack
Node node = q.First.Value;
q.RemoveFirst();
stk.Push(node);
// insert its left and right children
// in the back of the deque
if (node.left != null )
q.AddLast(node.left);
if (node.right != null )
q.AddLast(node.right);
nodeCount--;
}
}
else //even level
{
while (nodeCount > 0)
{
// dequeue node from the back & push it
// to stack
Node node = q.Last.Value;
q.RemoveLast();
stk.Push(node);
// inserts its right and left children
// in the front of the deque
if (node.right != null )
q.AddFirst(node.right);
if (node.left != null )
q.AddFirst(node.left);
nodeCount--;
}
}
level++;
}
// pop all nodes from stack and
// push them in the beginning of the list
while (stk.Count != 0)
{
push(stk.Peek());
stk.Pop();
}
Console.WriteLine( "Created DLL is : " );
printList(head);
}
// Driver program to test above functions
public static void Main(String[] args)
{
// Let us create binary tree as shown in above diagram
BinaryTree tree = new BinaryTree();
tree.root = new Node(1);
tree.root.left = new Node(2);
tree.root.right = new Node(3);
tree.root.left.left = new Node(4);
tree.root.left.right = new Node(5);
tree.root.right.left = new Node(6);
tree.root.right.right = new Node(7);
tree.root.left.left.left = new Node(8);
tree.root.left.left.right = new Node(9);
tree.root.left.right.left = new Node(10);
tree.root.left.right.right = new Node(11);
// tree.root.right.left.left = new Node(12);
tree.root.right.left.right = new Node(13);
tree.root.right.right.left = new Node(14);
// tree.root.right.right.right = new Node(15);
tree.spiralLevelOrder(tree.root);
}
} /* This code contributed by PrinciRaj1992 */ |
<script> /* Javascript program to convert Binary Tree into Doubly Linked List where the nodes are represented spirally */ // A binary tree node class Node { constructor(data)
{
this .data = data;
this .left = null ;
this .right = null ;
}
} var root = null ;
var head = null ;
/* Given a reference to a node, inserts the node on the front of the list. */ function push(node)
{ // Make right of given node as head and left as
// NULL
node.right = head;
node.left = null ;
// change left of head node to given node
if (head != null )
head.left = node;
// move the head to point to the given node
head = node;
} // Function to prints contents of DLL function printList(node)
{ while (node != null )
{
document.write(node.data + " " );
node = node.right;
}
} /* Function to print corner node at each level */ function spiralLevelOrder(root)
{ // Base Case
if (root == null )
return ;
// Create an empty deque for doing spiral
// level order traversal and enqueue root
var q = [];
q.unshift(root);
// create a stack to store Binary Tree nodes
// to insert into DLL later
var stk = [];
var level = 0;
while (q.length != 0)
{
// nodeCount indicates number of Nodes
// at current level.
var nodeCount = q.length;
// Dequeue all Nodes of current level and
// Enqueue all Nodes of next level
if ((level & 1) % 2 != 0) //odd level
{
while (nodeCount > 0)
{
// dequeue node from front & push it to
// stack
var node = q[0];
q.shift();
stk.push(node);
// insert its left and right children
// in the back of the deque
if (node.left != null )
q.push(node.left);
if (node.right != null )
q.push(node.right);
nodeCount--;
}
}
else //even level
{
while (nodeCount > 0)
{
// dequeue node from the back & push it
// to stack
var node = q[q.length-1];
q.pop();
stk.push(node);
// inserts its right and left children
// in the front of the deque
if (node.right != null )
q.unshift(node.right);
if (node.left != null )
q.unshift(node.left);
nodeCount--;
}
}
level++;
}
// pop all nodes from stack and
// push them in the beginning of the list
while (stk.length != 0)
{
push(stk[stk.length-1]);
stk.pop();
}
document.write( "Created DLL is :<br>" );
printList(head);
} // Driver program to test above functions // Let us create binary tree as shown in above diagram root = new Node(1);
root.left = new Node(2);
root.right = new Node(3);
root.left.left = new Node(4);
root.left.right = new Node(5);
root.right.left = new Node(6);
root.right.right = new Node(7);
root.left.left.left = new Node(8);
root.left.left.right = new Node(9);
root.left.right.left = new Node(10);
root.left.right.right = new Node(11);
// tree.root.right.left.left = new Node(12); root.right.left.right = new Node(13);
root.right.right.left = new Node(14);
// tree.root.right.right.right = new Node(15); spiralLevelOrder(root); // This code is contributed by itsok. </script> |
Created DLL is: 1 2 3 7 6 5 4 8 9 10 11 13 14
Time Complexity: O(n), as we are using a loop to traverse n times. Where n is the number of nodes in the tree.
Auxiliary Space: O(n), as we are using extra space for dequeue and stack.