Open In App

C# | Type.GetEnumName() Method

Type.GetEnumName(Object) Method is used to return the name of the constant which has the specified value for the current enumeration type.
 

Syntax:  



public virtual string GetEnumName (object value);

Here, it takes the value whose name is to be retrieved.
Return Value: This method returns the name of the member of the current enumeration type which has the specified value. If no such constant is found then it will return null.
Exceptions:  

Below programs illustrate the use of the above-discussed method:
Example 1: 






// C# program to demonstrate the
// Type.GetEnumName(Object) Method
using System;
using System.Globalization;
using System.Reflection;
 
class GFG {
 
    // Defining enum ABC
    enum ABC {A, B, C}
 
    // Main Method
    public static void Main()
    {
 
        // Creating try-catch block
        // to handle exceptions
        try {
 
            // Creating and initializing object
            // of ABC with instance of enum ABC
            ABC a = ABC.A;
 
            // Declaring and initializing
            // object of Type
            Type type = a.GetType();
 
            string obj = type.GetEnumName(a);
 
            Console.WriteLine("Name of constant is: " + obj);
        }
 
        // catch ArgumentNullException here
        catch (ArgumentNullException e)
        {
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Output: 
Name of constant is: A

 

Example 2: For ArgumentException




// C# program to demonstrate the
// Type.GetEnumName(Object) Method
using System;
using System.Globalization;
using System.Reflection;
 
class GFG {
 
    // Defining enum ABC
    enum ABC {A, B, C}
 
    // Main Method
    public static void Main()
    {
 
        // Creating try-catch block
        // to handle exceptions
        try {
 
            // Creating and initializing object
            // of ABC with instance of enum ABC
            ABC a = ABC.A;
 
            // Declaring and initializing
            // object of Type
            Type type = typeof(int);
 
            string obj = type.GetEnumName(a);
 
            Console.WriteLine("Name of constant is: " + obj);
        }
 
        // catch ArgumentNullException here
        catch (ArgumentNullException e)
        {
            Console.WriteLine("value is null. ");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
 
        // catch ArgumentException here
        catch (ArgumentException e)
        {
            Console.WriteLine("The current type is not an Enumeration.");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Output: 
The current type is not an Enumeration.
Exception Thrown: System.ArgumentException

 

Example 3: For ArgumentNullException




// C# program to demonstrate the
// Type.GetEnumName(Object) Method
using System;
using System.Globalization;
using System.Reflection;
 
class GFG {
 
   // Defining enum ABC
    enum ABC {A, B, C}
 
    // Main Method
    public static void Main()
    {
 
        // Creating try-catch block
        // to handle exceptions
        try {
 
            // Creating and initializing object
            // of ABC with instance of enum ABC
            ABC a = ABC.A;
 
            // Declaring and initializing
            // object of Type
            Type type = typeof(int);
 
            string obj = type.GetEnumName(null);
 
            Console.WriteLine("Name of constant is " + obj);
        }
 
        // catch ArgumentNullException here
        catch (ArgumentNullException e)
        {
            Console.WriteLine("value is null. ");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
 
        // catch ArgumentException here
        catch (ArgumentException e)
        {
            Console.WriteLine("The current type is not an Enumeration.");
            Console.Write("Exception Thrown: ");
            Console.Write("{0}", e.GetType(), e.Message);
        }
    }
}

Output: 
value is null. 
Exception Thrown: System.ArgumentNullException

 

Reference:


Article Tags :
C#