In C#, Math.Sqrt() is a Math class method which is used to calculate the square root of the specified number. Sqrt is a slower computation. It can be cached for a performance boost. Syntax:
public static double Sqrt(double d)
Parameter:
d: Number whose square root is to be calculated and type of this parameter is System.Double.
Return Type: This method returns the square root of d. If d is equal to NaN, NegativeInfinity, or PositiveInfinity, that value is returned. The return type of this method is System.Double. Examples:
Input : Math.Sqrt(81) Output : 9 Input : Math.Sqrt(-81) Output : NaN Input : Math.Sqrt(0.09) Output : 0.3 Input : Math.Sqrt(0) Output : 0 Input : Math.Sqrt(-0) Output : 0
Below C# programs illustrate the working of Math.Sqrt():
- Program 1: When the argument is positive double value then this method returns the square root of a given value.
// C# program to illustrate the // Math.Sqrt() method using System;
class GFG {
// Main Method
public static void Main()
{
double x = 81;
// Input positive value, Output square root of x
Console.Write(Math.Sqrt(x));
}
} |
9
- Program 2: When the argument is Negative, this method will return NaN.
// C# program to illustrate the Math.Sqrt() // method when the argument is Negative using System;
class GFG {
// Main method
public static void Main()
{
double x = -81;
// Input Negative value, Output square root of x
Console.Write(Math.Sqrt(x));
}
} |
NaN
- Program 3: When the argument is double value with decimal places, then this method will return the square root of a given value.
// C# program to illustrate the Math.Sqrt() // method when the argument is double value // with decimal places using System;
class GFG {
// Main Method
public static void Main()
{
double x = 0.09;
// Input value with decimal places,
// Output square root of x
Console.Write(Math.Sqrt(x));
}
} |
0.3
- Program 4: When the argument is positive or negative Zero, then it will return the result as Zero.
// C# program to illustrate the Math.Sqrt() // method when the argument is positive // or negative Zero using System;
class GFG {
// Main Method
public static void Main()
{
double x = 0;
// Input value positive Zero, Output
// square root of x
Console.WriteLine(Math.Sqrt(x));
double y = -0;
// Input value Negative Zero,
// Output square root of y
Console.Write(Math.Sqrt(y));
}
} |
0 0
Note: If the value is too large then it gives the compile time error as error CS1021: Integral constant is too large. Reference: https://msdn.microsoft.com/en-us/library/system.math.sqrt