Aptitude | Progressions | Question 2

Find the Sum of series: 2, 6, 10, 14, 18, 22, 26, 30
(A) 32
(B) 88
(C) 128
(D) 110

Answer: (C)
Explanation: Sum of AP = (n/2)[2a+(n-1)d]
= 4*[4+7*4]
=128

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