A box having 5 black and 3 brown flags. Another box having 4 black and 6 brown flags. If one flag is drawn from each box.
Find the probability that both flags are of different color.
(A) 21/40
(B) 10/19
(C) 3/8
(D) 3/10
Answer: (A)
Explanation:
Box 1 consists of 5 black and 3 brown flags.
Box 2 consists of 4 black and 6 brown flags.
So if we select black flags from box 1 we have to select brown flags from box2 according to the question and probability of that is
P1= 5/8 * 6/10
If we select brown flags from box 1 we have to select black flags from box2 according to the question and probability of that is
P2=3/8 * 4/10
So the answer is P1+P2= 21/40