Open In App

Aptitude | GATE CS 1998 | Question 68

Let (A, *) be a semi group. Furthermore, for every a and b in A, if a ≠ b, then a*b ≠ b*a.

a. Show that for every a in A  a*a = a



b. Show that for every a, b in A  a*b*a = a

c. Show that for every a, b, c in A  a*b*c = a*c

Answer:
Explanation:
Quiz of this Question
Please comment below if you find anything wrong in the above post



Article Tags :