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Aptitude | Algebra | Question 6

If the value of b2 + 1b2 = 1, then find the value of b3 + 1b3

(A)



-1/12

(B)



-2

(C)

-4

(D)

None of the above

Answer: (D)
Explanation:

E = (b + 1b)(b2 - 1 + 1b2)

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