Consider the relation R (ABCDE):
FD = { A → B, B → C, C → D, D → E}
Find out the highest normal form.
(A) 1 NF
(B) 2 NF
(C) 3 NF
(D) BCNF
Answer: (B)
Explanation: Here candidate Key is A and B -> C , C -> D , D -> E all are. (Non prime attribute -> Non prime attribute.).
This type of FD must not be present in 3NF therefore highest normal form of this FDs are 2NF.
Option (B) is correct.
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