Algorithms | Analysis of Algorithms | Question 18

Consider the following function,

 int unknown(int n) {
    int i, j, k = 0;
    for (i  = n/2; i <= n; i++)
        for (j = 2; j <= n; j = j * 2)
            k = k + n/2;
    return k;
 }

What is the time complexity of the function? (GATE CS 2013)

(A)

n^2

(B)

n logn

(C)

n^3

(D)

n^3 logn 

Answer: (B)
Explanation:

In the below explanation, \’^\’ is used to represent exponent: The outer loop runs n/2 or Theta(n) times. The inner loop runs (Logn) times (Note that j is multiplied by 2 in every iteration). So the overall time complexity is nLogn.

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