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8085 program to find 1’s and 2’s complement of 16-bit number

Prerequisite – 8085 program to find 1’s and 2’s complement of 8-bit number Problem – – Write a program to find 1’s and 2’s complement of 16-bit number where starting address is 2000 and the number is stored at 3000 memory address and store result into 3002 and 3004 memory address. Example – Algorithm –

  1. Load a 16-bit number from memory 3000 into a register pair (H-L)
  2. Move content of register L to accumulator
  3. Complement content of accumulator
  4. Move content of accumulator to register L
  5. Move content of register H to accumulator
  6. Complement content of accumulator
  7. Move content of accumulator to register H
  8. Store content of register pair in memory 3002 (1’s complement)
  9. Increment content of register pair by 1
  10. Store content of register pair in memory 3004 (2’s complement)
  11. Stop

Program –

Memory Mnemonics Operands Comment
2000 LHLD [3000] [H-L] <- [3000]
2003 MOV A, L [A] <- [L]
2004 CMA   [A] <- [A^]
2005 MOV L, A [L] <- [A]
2006 MOV A, H [A] <- [H]
2007 CMA   [A] <- [A^]
2008 MOV H, A [H] <- [A]
2009 SHLD [3002] 1’s complement
200C INX H [H-L] <- [H-L] + 1
200D SHLD [3004] 2’s complement
2010 HLT   Stop

Explanation –

  1. A is an 8-bit accumulator which is used to load and store the data
  2. LHLD is used to load register pair H-L direct using 16-bit address (3 Byte instruction)
  3. MOV is used to transfer the data from accumulator to register(any) or register(any) to accumulator (1 Byte)
  4. CMA is used to complement content of accumulator (1 Byte instruction)
  5. SHLD is used to store data from register pair H-L into memory direct using 16-bit address (3 Byte instruction)
  6. INX is used to increase H-L register pair by 1 (1 Byte instruction)
  7. HLT is used to halt the program

Advantages of using 1’s and 2’s complement:

Disadvantages of using 1’s and 2’s complement:

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