Javascript Program to Find the Mth element of the Array after K left rotations

Given non-negative integers K, M, and an array arr[] with N elements find the M^th element of the array after K left rotations.

Examples:

Input: arr[] = {3, 4, 5, 23}, K = 2, M = 1
Output: 5
Explanation: 
The array after first left rotation a₁[ ] = {4, 5, 23, 3}
The array after second left rotation a₂[ ] = {5, 23, 3, 4}
1st element after 2 left rotations is 5.

Input: arr[] = {1, 2, 3, 4, 5}, K = 3, M = 2
Output: 5 
Explanation: 
The array after 3 left rotation has 5 at its second position.

Naive Approach: The idea is to Perform Left rotation operation K times and then find the M^th element of the final array.

Time Complexity: O(N * K)
Auxiliary Space: O(N)

Efficient Approach: To optimize the problem, observe the following points:
1. If the array is rotated N times it returns the initial array again.

   For example, a[ ] = {1, 2, 3, 4, 5}, K=5 then the array after 5 left rotation a₅[ ] = {1, 2, 3, 4, 5}.

   Therefore, the elements in the array after Kth rotation is the same as the element at index K%N in the original array.
2. The Mth element of the array after K left rotations is
   

   { (K + M - 1) % N }th

   element in the original array.


Below is the implementation of the above approach:

JavaScript

<script>

// Javascript program for the above approach 

    // Function to return Mth element of
    // array after k left rotations
    function getFirstElement(a , N , K , M) {

        // The array comes to original state
        // after N rotations
        K %= N;

        // Mth element after k left rotations
        // is (K+M-1)%N th element of the
        // original array
        var index = (K + M - 1) % N;

        var result = a[index];

        // Return the result
        return result;
    }

    // Driver code
    

        // Array initialization
        var a = [ 3, 4, 5, 23 ];

        // Size of the array
        var N = a.length;

        // Given K rotation and Mth element
        // to be found after K rotation
        var K = 2, M = 1;

        // Function call
        document.write(getFirstElement(a, N, K, M));

// This code contributed by gauravrajput1 

</script>


Output:

5



Time complexity: O(1)
Auxiliary Space: O(1)

Please refer complete article on Find the Mth element of the Array after K left rotations for more details!
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