Sudo Placement | Special Subsequences
Last Updated :
11 Jul, 2025
Given a non-empty string S containing only lowercase letters, print all ‘Special Subsequences’ of S. For Instance, “ab” has the following Special Subsequences-: { “A”, “AB”, “Ab”, “B”, “a”, “aB”, “ab”, “b” }.
Note : Consider only the non-empty special Subsequences of S.
Examples:
Input : S = "a"
Output : { "A", "a" }
Input : S = "ab"
Output : { "A", "AB", "Ab", "B", "a", "aB", "ab", "b" }
Prerequisite : Subsequences of String
Approach : This is a slight variation, to the classic problem, printing the subsequences of a string. Let's say we have a recursive function generateSubsequences(input, i) that prints all the special subsequences of input string upto ith position. Let the current position be i in the input string, then there are three possibilities:
- Include input[i] in the output string as it is and call generateSubsequences(input, i + 1)
- Exclude input[i] in the output string and call generateSubsequence(str, i + 1), or
- Include the upper case form of input[i] and call generateSubsequences(str, i + 1). Do remember to first remove the currently added character from the output string.
Below is the implementation of above approach.
C++
// C++ Program to find all special subsequences
// of the given type
#include <bits/stdc++.h>
using namespace std;
// Function to generate the required subsequences
void generateSubsequences(string input, string output,
int idx, vector<string>& ans)
{
// If the index pointer has reached the
// end of input string
if (input[idx] == '\0') {
// Skip empty (" ") subsequence
if (output.size())
ans.push_back(output);
return;
}
// Exclude current character in output string
generateSubsequences(input, output, idx + 1, ans);
// Include current character in output string
output += input[idx];
generateSubsequences(input, output, idx + 1, ans);
// Remove the current included character and
// and include it in its uppercase form
output.pop_back();
char upper = input[idx];
upper = toupper(upper);
output += upper;
generateSubsequences(input, output, idx + 1, ans);
}
// Function to print the required subsequences
void printSubsequences(string S)
{
// Output String to store every subsequence
string output;
// Set of strings that will store all special
// subsequences in lexicographical sorted order
vector<string> ans;
generateSubsequences(S, output, 0, ans);
// Sort the strings to print in sorted order
sort(ans.begin(), ans.end());
for (auto str : ans)
cout << str << " ";
}
// Driver Code
int main()
{
string S = "ab";
printSubsequences(S);
return 0;
}
Java
// Java Program to find all special subsequences
// of the given type
import java.util.*;
import java.io.*;
public class SpecialSubsequences {
// Function to generate the required subsequences
public static void generateSubsequences(String input, String output,
int index, ArrayList<String> ans)
{
// If the index pointer has reached the
// end of input string
if(index == input.length()){
// Skip empty (" ") subsequence
if(output.length() != 0){
ans.add(output);
}
return;
}
//Exclude the character in the output string
generateSubsequences(input, output, index+1, ans);
//Include the current character as it is
output += String.valueOf(input.charAt(index));
generateSubsequences(input, output, index+1, ans);
//Include the current character in its upper case form
//To remove the last character, we generate a substring till the
//second last character
output = output.substring(0, output.length()-1);
output += String.valueOf(
Character.toUpperCase(input.charAt(index)));
generateSubsequences(input, output, index+1, ans);
}
// Function to print the required subsequences
public static void printSubsequences(String s){
// Output String to store every subsequence
String output = "";
// Set of strings that will store all special
// subsequences in lexicographical sorted order
ArrayList<String> ans = new ArrayList<>();
generateSubsequences(s, output, 0, ans);
//Sort the strings to print in the sorted order
Collections.sort(ans);
for(String str: ans){
System.out.print(str+" ");
}
System.out.println();
}
//Driver code
public static void main(String[] args){
String s = "ab";
printSubsequences(s);
}
}
Python3
# Python3 program to find all special subsequences
# of the given type
from typing import List
# Function to generate the required subsequences
def generateSubsequences(input: str, output: str,
idx: int, ans: List[str]) -> None:
# If the index pointer has reached the
# end of input string
if idx == len(input):
# Skip empty (" ") subsequence
if (len(output)):
ans.append(output)
return
# Exclude current character in output string
generateSubsequences(input, output, idx + 1, ans)
# Include current character in output string
output += input[idx]
generateSubsequences(input, output, idx + 1, ans)
# Remove the current included character and
# and include it in its uppercase form
output = output[:-1]
upper = input[idx]
upper = upper.upper()
output += upper
generateSubsequences(input, output, idx + 1, ans)
# Function to print the required subsequences
def printSubsequences(S: str) -> None:
# Output String to store every subsequence
output = ""
# Set of strings that will store all special
# subsequences in lexicographical sorted order
ans = []
generateSubsequences(S, output, 0, ans)
# Sort the strings to print in sorted order
ans.sort()
for string in ans:
print(string, end = " ")
# Driver Code
if __name__ == "__main__":
S = "ab"
printSubsequences(S)
# This code is contributed by sanjeev2552
C#
// C# Program to find all special subsequences
// of the given type
using System;
using System.Collections.Generic;
public class SpecialSubsequences {
// Function to generate the required subsequences
public static void generateSubsequences(string input, string output,
int index, List<string> ans)
{
// If the index pointer has reached the
// end of input string
if(index == input.Length){
// Skip empty (" ") subsequence
if(output.Length != 0){
ans.Add(output);
}
return;
}
//Exclude the character in the output string
generateSubsequences(input, output, index+1, ans);
//Include the current character as it is
output += input[index];
generateSubsequences(input, output, index+1, ans);
//Include the current character in its upper case form
//To remove the last character, we generate a substring till the
//second last character
output = output.Substring(0, output.Length-1);
output += char.ToUpper(input[index]);
generateSubsequences(input, output, index+1, ans);
}
// Function to print the required subsequences
public static void printSubsequences(string s){
// Output string to store every subsequence
string output = "";
// Set of strings that will store all special
// subsequences in lexicographical sorted order
List<string> ans = new List<string>();
generateSubsequences(s, output, 0, ans);
//Sort the strings to print in the sorted order
ans.Sort(StringComparer.Ordinal);
foreach(string str in ans){
Console.Write(str+" ");
}
Console.WriteLine();
}
//Driver code
public static void Main(){
string s = "ab";
printSubsequences(s);
}
}
// This code is contributed by Utkarsh
JavaScript
// Javascript Program to find all special subsequences
// of the given type
// Function to generate the required subsequences
function generateSubsequences(input, output,idx, ans)
{
// If the index pointer has reached the
// end of input string
if (idx == input.length)
{
// Skip empty (" ") subsequence
if (output.length)
ans.push(output);
return;
}
// Exclude current character in output string
generateSubsequences(input, output, idx + 1, ans);
// Include current character in output string
output += input[idx];
generateSubsequences(input, output, idx + 1, ans);
// Remove the current included character and
// and include it in its uppercase form
output=output.slice(0,-1);
let upper = input[idx];
upper = upper.toUpperCase();
output += upper;
generateSubsequences(input, output, idx + 1, ans);
}
// Function to print the required subsequences
function printSubsequences(S)
{
// Output String to store every subsequence
let output="";
// Set of strings that will store all special
// subsequences in lexicographical sorted order
let ans=[];
generateSubsequences(S, output, 0, ans);
// Sort the strings to print in sorted order
ans.sort();
for (let str in ans)
console.log(ans[str]+" ");
}
// Driver Code
let S = "ab";
printSubsequences(S);
// This code is contributed by Pushpesh Raj.
OutputA AB Ab B a aB ab b
Time Complexity : O(3N), where N is the size of string.
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