Check if the number is divisible 43 or not

Given a number N, the task is to check whether the number is divisible by 43 or not. 
Examples:

Input: N = 2795 
Output: yes 
Explanation: 
43 * 65 = 2795
Input: N = 11094 
Output: yes 
Explanation:
43 * 258 = 11094 

Approach: The divisibility test of 43 is: 

1. Extract the last digit.
2. Add 13 * last digit from the remaining number obtained after removing the last digit.
3. Repeat the above steps until a two-digit number, or zero, is obtained.
4. If the two-digit number is divisible by 43, or it is 0, then the original number is also divisible by 43.

For example:

If N = 11739

Step 1:
  N = 11739
  Last digit = 9
  Remaining number = 1173
  Adding 13 times last digit
  Resultant number = 1173 + 13*9 = 1290

Step 2:
  N = 1290
  Since 129 is divisible by 43 as 43 * 3 = 129

Therefore N = 11739 is also divisible by 43

Below is the implementation of the above approach: 

C++

// C++ program to check whether a number
// is divisible by 43 or not

#include<bits/stdc++.h>
#include<stdlib.h>

using namespace std;
// Function to check if the number is  divisible by 43 or not 
bool isDivisible(int n)  
{
    int d;
    // While there are at least two digits 
    while (n / 100) 
    {
 
        // Extracting the last 
        d = n % 10;
 
        // Truncating the number 
        n /= 10;
 
        // adding thirteen times the last 
        // digit to the remaining number 
        n = abs(n+(d * 13));
    }
    // Finally return if the two-digit
    // number is divisible by 43 or not
    return (n % 43 == 0) ;
}

// Driver Code 
int main() {
    int N = 2795;
 
    if (isDivisible(N)) 
        cout<<"Yes"<<endl ;
    else 
        cout<<"No"<<endl ;
   
     return 0;     
}    

// This code is contributed by ANKITKUMAR34

Java

// Java program to check whether a number
// is divisible by 43 or not
class GFG
{

// Function to check if the number is  divisible by 43 or not 
static boolean isDivisible(int n)  
{
    int d;
    // While there are at least two digits 
    while ((n / 100) > 0) 
    {
  
        // Extracting the last 
        d = n % 10;
  
        // Truncating the number 
        n /= 10;
  
        // adding thirteen times the last 
        // digit to the remaining number 
        n = Math.abs(n+(d * 13));
    }
    // Finally return if the two-digit
    // number is divisible by 43 or not
    return (n % 43 == 0) ;
}
 
// Driver Code 
public static void main(String[] args) {
    int N = 2795;
  
    if (isDivisible(N)) 
        System.out.print("Yes");
    else
        System.out.print("No");
    
 }     
}    
 
// This code is contributed by PrinciRaj1992

Python 3

# Python program to check whether a number
# is divisible by 43 or not

# Function to check if the number is 
# divisible by 43 or not 
def isDivisible(n) : 

    # While there are at least two digits 
    while n // 100 : 

        # Extracting the last 
        d = n % 10

        # Truncating the number 
        n //= 10

        # Adding thirteen  times the last 
        # digit to the remaining number 
        n = abs(n+(d * 13))

    # Finally return if the two-digit
    # number is divisible by 43 or not
    return (n % 43 == 0) 

# Driver Code 
if __name__ == "__main__" : 
    
    N = 2795

    if (isDivisible(N)): 
        print("Yes") 
    else : 
        print("No") 

C#

// C# program to check whether a number
// is divisible by 43 or not
using System; 
        
class GFG 
{ 
    
// Function to check if the number is divisible by 43 or not 
static bool isDivisible(int n) 
{
    int d;
    
    // While there are at least two digits 
    while (n / 100 > 0) 
    {

        // Extracting the last 
        d = n % 10;

        // Truncating the number 
        n /= 10;

        // adding thirteen times the last 
        // digit to the remaining number 
        n = Math.Abs(n + (d * 13));
    }
    
    // Finally return if the two-digit
    // number is divisible by 43 or not
    return (n % 43 == 0) ;
}

// Driver Code 
public static void Main() 
{ 
    int N = 2795;

    if (isDivisible(N)) 
        Console.WriteLine("Yes"); 
    else
        Console.WriteLine("No");     
} 
}

// This code is contributed by AbhiThakur

JavaScript

<script>
//javascript program to check whether a number
// is divisible by 43 or not

// Function to check if the number is divisible by 43 or not
function isDivisible(n)
{
    let d;
    // While there are at least two digits
    while(parseInt(n/100) > 0)
    {

        // Extracting the last
        d = n % 10;

        // Truncating the number
    n = parseInt(n / 10)

        // adding thirteen times the last
        // digit to the remaining number
        n = Math.abs(n+(d * 13));
    }
    // Finally return if the two-digit
    // number is divisible by 43 or not
    return (n % 43 == 0) ;
}

// Driver Code
    let N = 2795;

    if (isDivisible(N))
        document.write("Yes");
    else
        document.write("No");

// This code is contributed by vaibhavrabadiya117.
</script>

Output:

Yes

Time Complexity: O(log₁₀N₎

Auxiliary Space: O(1)

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