Zero Initialization in C++
Last Updated :
15 Mar, 2023
Setting the initial value of an object to zero is called zero initialization.
Syntax:
static T object;
Tt = {} ;
T {} ;
char array [n] = " ";
Zero initialization is performed in the following situations:-
- Zero is initialized for every named variable with static or thread-local storage duration that is not subject to constant initialization (since C++14), before any other initialization.
- Zero is initialized as part of the value-initialization sequence for non-class types and for members of value-initialized class types that have no constructors.
- When a character array is initialized with a string literal which is very short, the remainder of the array is zero-initialized.
The effects of zero-initialization are:
- If T is a scalar type, the object is initialized to the value obtained by converting the integer literal 0 to T.
- If T is a non-union class type, each non-static data member and each base-class subobject is zero-initialized and padding is initialized to zero bits.
- If T is a union type, the object’s first non-static named data member is zero-initialized and padding is initialized to zero bits.
- If T is an array type, each array element is zero-initialized.
- If T is a reference type, no initialization is performed.
Key Points:
- The static and thread-local variables are first zero-initialized and then initialized again as specified in the program, e.g. in the starting of a program, function-local static is first zero-initialized, and then its constructor is called when the function is first entered. If there is no initializer for the declaration of a non-class static, then default initialization does nothing, leaving the result of the earlier zero-initialization unmodified.
- A pointer which is zero-initialized is called a null pointer, even if the value of the null pointer is not integral zero.
Below program illustrates zero initialization in C++:
CPP
#include <iostream>
#include <string>
struct foo {
int x, y, z;
};
double f[3];
int * p;
std::string s;
int main( int argc, char * argv[])
{
foo x = foo();
std::cout << x.x << x.y << x.z << '\n' ;
return 0;
}
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In this example logic is same but program is quite different than above example. Below is another method of Zero Initialization in C++.
C++
#include <iostream>
#include <string>
using namespace std;
struct S {
int g, q, r;
};
double f[3];
int * p;
string u;
int main( int argc, char *[])
{
delete p;
static int n = argc;
cout << "n=" << n << '\n' ;
S g = S();
cout << "g={" << g.g << " " << g.q << " " << g.r
<< "} \n" ;
return 0;
}
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