Yacc Program to evaluate a given arithmetic expression
Prerequisite – Introduction to YACC
Problem: Write a YACC program to evaluate a given arithmetic expression consisting of ‘+’, ‘-‘, ‘*’, ‘/’ including brackets.
Examples:
Input: 7*(5-3)/2
Output: 7
Input: 6/((3-2)*(-5+2))
Output: -2
Lexical Analyzer Source Code:
C
%{
#include "y.tab.h"
extern yylval;
%}
%%
[0-9]+ {
yylval = atoi (yytext);
return NUMBER;
}
[a-zA-Z]+ { return ID; }
[ \t]+ ;
\n { return 0; }
. { return yytext[0]; }
%%
|
Parser Source Code:
C
%{
#include <stdio.h>
%}
%token NUMBER ID
%left '+' '-'
%left '*' '/'
%%
E : T {
printf ( "Result = %d\n" , $$);
return 0;
}
T :
T '+' T { $$ = $1 + $3; }
| T '-' T { $$ = $1 - $3; }
| T '*' T { $$ = $1 * $3; }
| T '/' T { $$ = $1 / $3; }
| '-' NUMBER { $$ = -$2; }
| '-' ID { $$ = -$2; }
| '(' T ')' { $$ = $2; }
| NUMBER { $$ = $1; }
| ID { $$ = $1; };
% %
int main() {
printf ( "Enter the expression\n" );
yyparse();
}
int yyerror( char * s) {
printf ( "\nExpression is invalid\n" );
}
|
Output:
Notes:
Yacc programs are generally written in 2 files one for lex with .l extension(for tokenization and send the tokens to yacc) and another for yacc with .y extension (for grammar evaluation and result evaluation).
Steps for execution of Yacc program:
yacc -d sample_yacc_program.y
lex sample_lex_program.l
cc lex.yy.c y.tab.c -ll
./a.out
Last Updated :
15 Dec, 2022
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