# XOR of every element of an Array with a given number K

Given an array arr and a number K, find the new array formed by performing XOR of the corresponding element from the given array with the given number K.

Examples:

Input: arr[] = { 2, 4, 1, 3, 5 }, K = 5
Output: 7 1 4 6 0
Explanation:
2 XOR 5 = 7
4 XOR 5 = 1
1 XOR 5 = 4
3 XOR 5 = 6
5 XOR 5 = 0

Input: arr[] = { 4, 75, 45, 42 }, K = 2
Output: 6 73 47 40

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

1. Traverse the given array.
2. Then calculate the XOR of each element with K.
3. Then store it as the element at that index in the output array.
4. Print the updated array.

Below is the implementation of the above approach.

## CPP

 `// C++ program to find XOR of every element ` `// of an array with a given number K ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to construct new array ` `void` `constructXORArray(``int` `A[], ``int` `n, ``int` `K) ` `{ ` `    ``int` `B[n]; ` ` `  `    ``// Traverse the array and ` `    ``// compute XOR with K ` `    ``for` `(``int` `i = 0; i < n; i++) ` `        ``B[i] = A[i] ^ K; ` ` `  `    ``// Print new array ` `    ``for` `(``int` `i = 0; i < n; i++) ` `        ``cout << B[i] << ``" "``; ` `    ``cout << endl; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `A[] = { 2, 4, 1, 3, 5 }; ` `    ``int` `K = 5; ` `    ``int` `n = ``sizeof``(A) / ``sizeof``(A); ` `    ``constructXORArray(A, n, K); ` ` `  `    ``int` `B[] = { 4, 75, 45, 42 }; ` `    ``K = 2; ` `    ``n = ``sizeof``(B) / ``sizeof``(B); ` `    ``constructXORArray(B, n, K); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find XOR of every element ` `// of an array with a given number K ` `import` `java.util.*; ` `class` `GFG ` `{ ` ` `  `// Function to construct new array ` `static` `void` `constructXORArray(``int` `A[], ``int` `n, ``int` `K) ` `{ ` `      `  `     ``int``[] B = ``new` `int``[n]; ` ` `  `    ``// Traverse the array and ` `    ``// compute XOR with K ` `    ``for` `(``int` `i = ``0``; i < n; i++) ` `        ``B[i] = A[i] ^ K; ` ` `  `    ``// Print new array ` `    ``for` `(``int` `i = ``0``; i < n; i++) ` `        ``System.out.print( B[i] +``" "``); ` `    ``System.out.println(); ` `} ` ` `  `// Driver code  ` `public` `static` `void` `main(String args[])  ` `{  ` `    ``int` `A[] = { ``2``, ``4``, ``1``, ``3``, ``5` `}; ` `    ``int` `K = ``5``; ` `    ``int` `n = A.length; ` `    ``constructXORArray(A, n, K); ` ` `  `    ``int` `B[] = { ``4``, ``75``, ``45``, ``42` `}; ` `    ``K = ``2``; ` `    ``n = B.length; ` `    ``constructXORArray(B, n, K); ` ` `  `} ` `} ` ` `  `// This code is contributed by shivanisinghss2110 `

## Python3

 `# Python program to find XOR of every element ` `# of an array with a given number K ` ` `  `# Function to construct new array ` `def` `constructXORArray(A, n, K): ` ` `  `    ``B ``=` `[``0``]``*``n; ` ` `  `    ``# Traverse the array and ` `    ``# compute XOR with K ` `    ``for` `i ``in` `range``(n): ` `        ``B[i] ``=` `A[i] ^ K; ` ` `  `    ``# Print new array ` `    ``for` `i ``in` `range``(n): ` `        ``print``(B[i], end``=``" "``); ` `    ``print``(); ` ` `  ` `  `# Driver code ` `if` `__name__ ``=``=` `'__main__'``: ` `    ``A ``=` `[ ``2``, ``4``, ``1``, ``3``, ``5` `]; ` `    ``K ``=` `5``; ` `    ``n ``=` `len``(A); ` `    ``constructXORArray(A, n, K); ` ` `  `    ``B ``=` `[ ``4``, ``75``, ``45``, ``42` `]; ` `    ``K ``=` `2``; ` `    ``n ``=` `len``(B); ` `    ``constructXORArray(B, n, K); ` `# This code contributed by sapnasingh4991 `

## C#

 `// C# program to find XOR of every element ` `// of an array with a given number K ` `using` `System; ` ` `  `class` `GFG ` `{ ` `  `  `// Function to construct new array ` `static` `void` `constructXORArray(``int` `[]A, ``int` `n, ``int` `K) ` `{ ` `       `  `     ``int``[] B = ``new` `int``[n]; ` `  `  `    ``// Traverse the array and ` `    ``// compute XOR with K ` `    ``for` `(``int` `i = 0; i < n; i++) ` `        ``B[i] = A[i] ^ K; ` `  `  `    ``// Print new array ` `    ``for` `(``int` `i = 0; i < n; i++) ` `        ``Console.Write( B[i] +``" "``); ` `    ``Console.WriteLine(); ` `} ` `  `  `// Driver code  ` `public` `static` `void` `Main(String []args)  ` `{  ` `    ``int` `[]A = { 2, 4, 1, 3, 5 }; ` `    ``int` `K = 5; ` `    ``int` `n = A.Length; ` `    ``constructXORArray(A, n, K); ` `  `  `    ``int` `[]B = { 4, 75, 45, 42 }; ` `    ``K = 2; ` `    ``n = B.Length; ` `    ``constructXORArray(B, n, K); ` `} ` `} ` ` `  `// This code is contributed by Rajput-Ji `

Output:

```7 1 4 6 0
6 73 47 40
```

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