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wxPython – IsSeparator() function in wx.MenuItem

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  • Last Updated : 09 Jun, 2020
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In this article we are going to learn about IsSeparator() function associated with wx.MenuItem class of wxPython. IsSeparator() function simply returns True if the item is a separator. An item can be declared/set as separator if it’s id is wx.ID_SEPARATOR.
No parameters are required by IsSeparator() function.




No parameters are required by IsSeparator() function.

Return Type:


Code Example:

import wx
class Example(wx.Frame):
    def __init__(self, *args, **kwargs):
        super(Example, self).__init__(*args, **kwargs)
    def InitUI(self):
        self.locale = wx.Locale(wx.LANGUAGE_ENGLISH)
        self.menubar = wx.MenuBar()
        self.fileMenu = wx.Menu()
        self.item = wx.MenuItem(self.fileMenu, wx.ID_SEPARATOR)
        self.item2 = wx.MenuItem(self.fileMenu, 1, '&Radio 2', helpString ="Check Help", kind = wx.ITEM_RADIO)
        self.item2.SetTextColour((79, 81, 230, 255)) = wx.StaticText(self, label ="", pos =(200, 200))
        self.menubar.Append(self.fileMenu, '&File')
        if self.item.IsSeparator()== True:
            # print if item is separator
            print("Item is Separator")
            # print if item is not separator
            print("Item is not Separator")
        self.SetSize((350, 250))
        self.SetTitle('Icons and shortcuts')
def main():
    app = wx.App()
    ex = Example(None)
if __name__ == '__main__':


Item is Separator

Output Window:

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