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Write a bash script to print a particular line from a file
  • Difficulty Level : Easy
  • Last Updated : 26 Sep, 2017


Given a file, name file.txt, out task is to write a bash script which print particular line from a file.

Content of file.txt:

I
love
reading
articles
at
geeks
for
geeks

Syntax in Bash Script

  1. awk :
    $>awk '{if(NR==LINE_NUMBER) print $0}' file.txt
  2. sed :
    $>sed -n LINE_NUMBERp file.txt
  3. head :
    $>head -n LINE_NUMBER file.txt | tail -n + LINE_NUMBER
    Here LINE_NUMBER is, 
    which line number you want to print

    Examples:

    Print a line from single file



    To print 4th line from the file then we will run following commands. The output of following lines will be “articles”.

    1. awk :
      $>awk '{if(NR==4) print $0}' file.txt
    2. sed :
      $>sed -n 4p file.txt 
    3. head :
      $>head -n 4 file.txt | tail -n + 4

    Print a line from multiple files

    Suppose we have two files, file1.txt and file2.txt, We can use the above commands and print particular line from multiple files by ‘&’.

    1. awk:
      $>awk '{if(NR==4) print $0}' file1.txt & awk '{if(NR==4) print $0}' file2.txt
    2. sed:
      $>sed -n 4p file1.txt & sed -n 4p file2.txt
    3. head:
      $>head -n 4 file1.txt | tail -n + 4 & head -n 4 file2.txt | tail -n + 4

    This article is contributed by Sahil Rajput. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

    Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

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